0.953948 is what I got from dividing pressure value by 760.
A.a low basket with plastic liner
112.5 g. The production of 50.00 g O2 requires 112.5 g H2O.
a) Write the partially balanced equation for the decomposition of water.
MM = 18.02 32.00
2H2O → O2 + …
Mass/g = 50.00
b) Calculate the <em>moles of O2
</em>
Moles of O2 = 50.00 g O2 × (1 mol O2/16.00 g O2) = 3.1250 mol O2
c) Calculate the <em>moles of water</em>
Moles of H2O = 3.1250 mol O2 × (2 mol H2O/1 mol O2)
= 6.2500 mol H2O
d) Calculate the mass of water
Mass of H2O = 6.2500 mol H2O × (18.02 g H2O/1 mol H2O)
= 112.5 g H2O
Answer:1.309 x 10^24 oxygen atoms
Explanation:
Molar mass of N2O4,= 2 x Molar mass of Nitrogen + 4 x Molar mass of Oxygen
= 2 x 14.01 + 4 x 16.0
= 92.02 g/mol
One mole of a substance is equal to 6.022 × 10²³ unit/ atoms/ molecules
In N2O4, there are 4 moles of Oxygen
if 92.02 g contains = 4 x 6.022 x 10 ^23 molecules
50.0 g wll contain= (4 x 6.022 x 10 ^23 x 50)/ 92.02g
1.309 x 10^24 oxygen atoms
