Given that the two swimmers competed and Ursula's speed is 60 m/min while Andre's speed is 48 m/min. The distance that the Ursula will catch up with Andre will be:
distance=(relative speed)×(time)
relative speed=60-48=12 m/min
the two swimmers met at a distance of:
12×1
=12 meters
Answer:
just multiply 7 by 21 and 21 by 7
like
2*21/7*21. + 10*7/21*7
41/147+ 70/147
111/147. Ans
Answer:
44.4%
Step-by-step explanation:
To calculate this, we proceed as follows.
we use the probability equation below;
P(A|B) = P(A and B) / P(B)
Applying the above to the scenario at hand;
P(red | car) = P(red and car) / P(car)
P(red and car) = 40% or simply 40/100 = 0.4
P(car) = 90% = 90/100 = 0.9
P(red | car) = 0.4/0.9
P(red | car) = 0.4444 which is = 44.44% ; to the nearest tenth of a percent = 44.4%
Answer:
the answer should be c.
Step-by-step explanation:
here's why....A uses 4 more which is adding. B uses 4 fewer which is subtracting and D does not complete so it should be C.
Reverse your steps to see if u get what the questions originally asked.
