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lisov135 [29]
3 years ago
8

Can someone help with this ??

Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0
I’m sorry but I can’t see the photo so can you tape it out so I can furthermore assist you
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Questions and Answers<br>1.<br>A is 40% of B. what percentages<br>Discuss<br>A<br>6090<br>B.​
ratelena [41]

Answer:

yeah thats right good job keep up the good work and keep doing ur thing good job

Step-by-step explanation:

5 0
3 years ago
The cost to mail a first-class letter used to be $0.40 the first ounce. Each additional ounce costs $0.20. Fractions of an ounce
Hitman42 [59]
$1.00 because the first ounce is 0.40 then you have to times the other 3 ounce by 0.20 then u would have $1.00
7 0
2 years ago
the audience in a theatre is made up of the following ratio: men:women:children 3:4:5. there are 348 people in the audience. cal
scoundrel [369]
There are 87 men 3 is the male ratio You add all the ratios 3+4+5=12 3/12×348 =87
7 0
3 years ago
A rectangle and an equilateral
jek_recluse [69]

Answer:

The area of the rectangle = 50 cm^2.

Step-by-step explanation:

Let the shortest side of the rectangle be x cm.

Perimeter of the rectangle is:

2x + 2(x + 5).

Perimeter of the triangle =  3 * 2x.

As they have the same perimeter:

2x + 2(x + 5) = 3*2x

2x + 2x + 10 = 6x

6x - 2x - 2x = 10

2x = 10

x = 5 cm.

So the area of the rectangle = x(x + 5)

= 5 * 10

= 50 cm^2.

4 0
3 years ago
The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard
PilotLPTM [1.2K]

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 8.59, \sigma = 0.63

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

This is 1 subtracted by the pvalue of Z when X = 9.08. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.08 - 8.59}{0.63}

Z = 0.78

Z = 0.78 has a pvalue of 0.7823

1 - 0.7823 = 0.2177

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

8 0
3 years ago
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