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Maslowich
3 years ago
9

I need help finding the midpoint and distance!!! Will mark brainliest

Mathematics
1 answer:
Valentin [98]3 years ago
3 0
Lol I’m taking the same stuff right now. Sorry to be but no cheating on homework. The formulas are long but you’ll get there
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I need help on this question can someone please help me?
Svetllana [295]

I really hate these algebra problems pretending to be geometry.  

Anyway angles B and D  are congruent in a parallelogram.  Geometry part done.

4n - 2 = 2n + 32

2n = 34

n = 17

Answer: 17, which is the 3rd choice

3 0
3 years ago
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Solve this answer<br> 5/3 + 2/5
salantis [7]
5/3+2/5=25/15+6/15=31/15=2 1/15

2 1/15 or 31/15

5 0
3 years ago
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R= 4/3(p-q) <br><br>solve for p ​
Naya [18.7K]

Answer = p=12-4 -12=17=18+19

p-q

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3 0
3 years ago
Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n
Mazyrski [523]

We can use the fact that, for |x|,

\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n

Notice that

\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1{1-x}\right]=\dfrac1{(1-x)^2}

so that

f(x)=\displaystyle\frac5{(1-x)^2}=5\frac{\mathrm d}{\mathrm dx}\left[\sum_{n=0}^\infty x^n\right]

f(x)=\displaystyle5\sum_{n=0}^\infty nx^{n-1}

f(x)=\displaystyle5\sum_{n=1}^\infty nx^{n-1}

f(x)=\displaystyle5\sum_{n=0}^\infty(n+1)x^n

By the ratio test, this series converges if

\displaystyle\lim_{n\to\infty}\left|\frac{(n+2)x^{n+1}}{(n+1)x^n}\right|=|x|\lim_{n\to\infty}\frac{n+2}{n+1}=|x|

so the series has radius of convergence R=1.

5 0
3 years ago
Please solve this, i will mark brainliest
Anton [14]

Answer:

k=-2

Step-by-step explanation:

Let's write the left hand side as a negative power, and 9 as a power of 3:

3^-^k=3^2 At this point, for the equality to still stand, the exponents have to be equal:

-k = 2 \rightarrow k=-2

7 0
2 years ago
Read 2 more answers
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