Solve by using the LCD. 4/x-5 + 1/x = x-1/x-5 (please help!!)

Mathematics

2 answers:

nikdorinn [45]3 years ago

7 0

Answer: x ≠ 5; x≠ 0

$\frac{4}{x-5}+\frac{1}{x}=\frac{x-1}{x-5}\\\\ \frac{4x+x-5}{x(x-5)}=\frac{x(x-1)}{x(x-5)} \\ 4x+x-5=x(x-1)\\ 5x-5 = x^{2}-x\\ x^{2} -6x+5=0\\(x-5)(x-1)=0\\$

because x≠ 5 => x - 5 ≠ 0

=> x - 1 = 0

⇔ x = 1

Step-by-step explanation:

Snezhnost [94]3 years ago

7 0

See attachment for math work and answer.

Reject x = 5.

Answer is x = 1.

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