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Dvinal [7]
3 years ago
10

1234567890 this question was written wrong

Mathematics
2 answers:
Assoli18 [71]3 years ago
7 0

Answer:

1+2+3+4+5+6+7+8+9+0=45

Step-by-step explanation:

MArishka [77]3 years ago
5 0
Lol do you want to ask it again?
You might be interested in
Suppose f is a continuous function on [-2, 2) such that
Leviafan [203]

Answer:

2. a and b only.

Step-by-step explanation:

We can check all of the given conditions to see which is true and which false.

a. f(c)=0 for some c in (-2,2).

According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.

b. the graph of f(-x)+x crosses the x-axis on (-2,2)

Let's test this condition, we will substitute x for the given values on the interval so we get:

f(-(-2))+(-2)

f(2)-2

-1-1=-3  lower limit

f(-2)+2

1+2=3 higher limit

according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.

c. f(c)<1 for all c in (-2,2)

even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.

The final answer is then 2. a and b only.

4 0
3 years ago
22.5+7(n-34) simplified
Aneli [31]
22.5 + 7n - 238 \\ 7n - 215.5
7 0
3 years ago
WILL GIVE BRAINLIEST, THANKS, AND 5STARS!<br> PLEASE HELP ME ANSWER THIS QUESTION
k0ka [10]

Answer:

h(.5)= -16(.5)^2 + 50

= 46

3 0
2 years ago
Given f(x)=x2+12x+26. Enter the quadratic function in vertex form in the box. f(x)=
makvit [3.9K]

Answer:

vertex(-6,-3)

Step-by-step explanation:

x^2+12+36-36+26

(x+6)^2-10

v=(-6,-10)

4 0
3 years ago
Use the graph of f below. Assume the entire function is graphed below.<br> Find the domain
enot [183]

ANSWER

The domain of the function is

- 3 \leqslant x \leqslant 6

or

[-3,6]

EXPLANATION

The domain of a function refers to the values of x for which the function is defined.

From the graph, we can see that the function begins at (-3,6) and ends at (6,-4).

Therefore the function is defined for x=-3 to x=6.

Hence the domain of the function is

- 3 \leqslant x \leqslant 6

or

[-3,6]

5 0
3 years ago
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