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2 years ago

Which is the equation of the line with slope 3 that contains point (-1, 5)?

Mathematics

2 answers:

Snezhnost [94]2 years ago

8 0

Y - 5 = 3 ( x + 1 )

i am a mathematics teacher. if anything to ask please pm me

Setler79 [48]2 years ago

3 0

The expression above is in a point-slope form which is:

y-y1 = m(x-x1)

Therefore, from the given problem:

m = 3
y1 = 5
x1 = -1

The transformed equation would be:

y-5 = 3(x+1) which is the first choice.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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$x+3y=12$

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Given:

x-intercept = 12

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To find the equation of line in the form $ax+by=c$ where $a,b,c$ are integers with no factor common to all three, and greater than or equal 0.

Solution:

The x-intercept is the point at which the line cuts the x-axis. The point of x-intercept is given as $(x,0)$

Thus, on point of the line is (12,0)

The y-intercept is the point at which the line cuts the y-axis. The point of y-intercept is given as $(0,y)$ .

Thus, on point of the line is (0,4)

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So, slope of the line can b given as:

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The slope intercept form of the equation of he line is given as:

$y=mx+b$

where $m$ represents slope of the line and $b$ represents the y-intercept.

So, the equation of the line can be given as:

$y=-\frac{1}{3}x+4$

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$3y=3.-\frac{1}{3}x+4(3)$

$3y=-x+12$

Adding $x$ both sides.

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$3y+x=12$

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