Answer:
Step-by-step explanation:
<h2>A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.
</h2><h2>y=-16x^2+129x+119
</h2><h2>y=−16x </h2><h2>2
</h2>
+129x+119
Answer:
The correct option is C) 36
Step-by-step explanation:
Consider the provided table:
x - y
1 - 1
2 - 4
3 - 9
4 - 16
Observe the pattern:
If we square the x value we can find the corresponding y value.
For example
2² = 4
Where 2 is x value and 4 is corresponding y value, similarly
3² = 9
4² = 16
Now we need to find the y value when x=6.
To find this simply square the x value that will gives us the corresponding y value.
6² = 36
Hence, the correct option is C) 36
I believe it would 15/8.
Tangent is Opposite/Adjacent so 15/8
Hope this helps! :)
