S=d/t ⇒d=s*t
s=speed
d=distance
t=time
The first train :
d=x
x=70 miles/h*t ⇒ x=70t (1)
The second train
d=360 miles - x
360 miles - x=80 miles/h*t ⇒360-x=80t ⇒ x=360-80t (2)
therefore, with the equations (1) and (2) we have a systeme of equations:
x=70t
x=360-80t
we can solve this system of equations by equalization method.
70t=360-80t
70t+80t=360
150t=360
t=360/150=2.4 (≈2 hour 24 minutes)
Answer: the first train meet with the second train in 2 hour 24 minutes.
6 and -3
6 + -3 = 3
6 x -3 = -18
Hope that helps!
Answer:(d): y=ax+b (a≠0); (d1)y=-4x+13
because of (d)⊥(d1) --> a.(-4)=-1 --> a=
(d): y=
+b. (d) pass through P(-1;-2) so we have
-2=(1/4).(-1)+b ---> b=
(d) y= 
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
x=10,−1
Answer:
By making y alone
Step-by-step explanation:
3y-14=16
+14 +14
3y= 30
divide 3 on both sides
y=10
Hope this helps!
