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Lelu [443]
2 years ago
7

Please help. What is the surface area. This is urgent!

Mathematics
2 answers:
riadik2000 [5.3K]2 years ago
8 0

Answer:

1733.28 in^2.

Step-by-step explanation:

The radius r = 1/2 the diameter = 1/2 *12 = 6 inches.

SA = 2*3.14*6^2 + 2*3.14*6*40

= 1733.28 in^2.

zloy xaker [14]2 years ago
3 0

Answer:1733.28

square inches I think

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Shortest distance to the origin y=1/2x^2 -4
IrinaK [193]
X=0 y=-2
y=0 x=4

The shortest distance has to be the perp bisector from origin to the midpoint of the line.
midpoint =(2,-1)  and distance from the (0,0) origin is sqrt(5) hence, sqrt(5).

6 0
3 years ago
A stadium has 45,000 seats. Seats sell for ​$30 in Section​ A, ​$24 in Section​ B, and ​$18 in Section C. The number of seats in
NikAS [45]

Answer:

About 90 seats per section.

hope this helps!

3 0
3 years ago
Please I need help it’s for a quiz I will give you a Brainly
tankabanditka [31]

Answer:

A

Step-by-step explanation:

Hopefully this helps

4 0
3 years ago
Read 2 more answers
Please helppp with this math question <333
Naya [18.7K]

Answer:

The average rate of change of the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1 is -1

Step-by-step explanation:

We are given the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1

We need to find average rate of change.

The formula used to find average rate of change is : Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}

We have b=-1 and a=-11

Finding g(b) = g(-1)

g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9

Finding g(a) = g(-11)

g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29

Finding average rate of change

Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1

So, the average rate of change of the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1 is -1

5 0
3 years ago
Name a pair of overlapping congruent triangles in each diagram. State whether the triangles are congruent by SSS, SAS, ASA, AAS,
MariettaO [177]

Answer:

ΔPTS≅ΔRTA by AAS axiom of congruency

Step-by-step explanation:

Consider ΔPQA and ΔRQS

∠PQA=∠RQS     (Vertically Opposite Angles)

∠QAP=∠QSR     (Complementary of two equal angles, ∠RAT and∠PST)

Due to angle sum property of a triangle, we come to the conclusion that

∠APQ=∠SRQ

Consider ΔPTS and ΔRTA

TA=TS  (Given)

∠RAT=∠PST(Given)

∠APQ=∠SRQ (Proved above)

Therefore, ΔPTS≅ΔRTA by AAS axiom of congruency.

8 0
3 years ago
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