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meriva
2 years ago
13

Group B 8x4=82

Mathematics
1 answer:
Semmy [17]2 years ago
7 0

Answer:

poop

Step-by-step explanation:

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What is the range?<br> 0,10,-24,-5,-5,3,3,-8,10
Nuetrik [128]

Answer:

-14

Step-by-step explanation:

Range is the difference between the lowest and highest values.

6 0
2 years ago
The measure of an inscribed circle of an angle is the measure of the intercepted arc
Andre45 [30]

Answer:

(the statement does not appear to be true)

Step-by-step explanation:

I don't think the statement is true, but you CAN compute the intercepted arc from the angle.

Note that BFDG is a convex quadrilateral, so its angles sum to 360. Since we know the inscribed circle touches the angle tangentially, angles BFD and BGD are both right angles, with a measure of 90 degrees.

Therefore, adding the angles together, we have:

alpha + 90 + 90 + <FDG = 360

Therefore, <FDG, the inscribed angle, is 180-alpha (ie, supplementary to alpha)

4 0
3 years ago
Jackie had $135 to spent at the mall she spent 29% of the money on a dress. Jackie spent $_ on the dress ?
dmitriy555 [2]

Jackie spent $39.15 on the dress.


6 0
3 years ago
(secx)dy/dx=e^(y+sinx), please help me solve the differential equation. Thanks :)
nalin [4]
First, you must know these formula  d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx

(secx)dy/dx=e^(y+sinx), implies  <span>dy/dx=cosx .e^(y+sinx), and then 
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of 
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that   d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
 finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is 
y = e^2. (e^sinx) +C, you can check this answer to calculate dy/dx
7 0
3 years ago
Read 2 more answers
Find first derivative f(x)= x² - 4 /x³ + 9 ​
vitfil [10]

Answer:

f'(x) = 2x + \frac{12}{x^{4} }

Step-by-step explanation:

differentiate using the power rule

\frac{d}{dx} ( ax^{n} ) = nax^{n-1}

Given

f(x) = x² - \frac{4}{x^3} + 9 = x² - 4x^{-3} + 9 , then

f'(x) = 2x + 12x^{-4} = 2x + \frac{12}{x^{4} }

5 0
2 years ago
Read 2 more answers
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