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meriva
2 years ago
13

Group B 8x4=82

Mathematics
1 answer:
Semmy [17]2 years ago
7 0

Answer:

poop

Step-by-step explanation:

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Find an equation in standard form for the hyperbola with vertices at (0, ±6) and foci at (0, ±9).
Dvinal [7]
<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:


..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation:  , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
4 0
3 years ago
Alma en peso ajugar ala ora que marca el reloj qué eran las 3 :45pm y terminó alas 5pm cuánto tiempo Jugo alma Alma empezó a jug
anzhelika [568]

Answer:

01:55:55

Step-by-step explanation:

1 horas 55 minutos 55 segundos

4 0
3 years ago
Helppppppppppppppppppppppppp
balandron [24]

Answer:

b.

Step-by-step explanation:

6 0
3 years ago
Please help me out!!!!!
Gnoma [55]
The last answer: 2 or 0

Explanation:

When you graph this function, it crosses the x-axis once. In other words, that means there is only 1 real zero and 2 imaginary complex zeros. In addition, imaginary solutions always come in pairs, so there can’t be a odd number of them such as 3.
8 0
3 years ago
A team of 17 softball players need to choose three players to refill the water cooler. How many different ways are there to sele
KATRIN_1 [288]
<h3>Answer: 680 different combinations</h3>

=======================================================

Explanation:

If order mattered, then we'd have 17*16*15 = 4080 different permutations. Notice how I started with 17 and counted down 1 at a a time until I had 3 slots to fill. We count down by 1 because each time we pick someone, we can't pick them again.

So we have 4080 different ways to pick 3 people if order mattered. But again order doesn't matter. All that counts is the group itself rather than the individual or how they rank. There are 3*2*1 = 6 ways to order any group of three people, which means there are 4080/6 = 680 different combinations possible.

An alternative is to use the nCr formula with n = 17 and r = 3. That formula is

_n C _r = \frac{n!}{r!*(n-r)!}

where the exclamation marks indicate factorials

5 0
3 years ago
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