Answer:

Step-by-step explanation:
Given
--- interval
Required
The probability density of the volume of the cube
The volume of a cube is:

For a uniform distribution, we have:

and

implies that:

So, we have:

Solve


Recall that:

Make x the subject

So, the cumulative density is:

becomes

The CDF is:

Integrate
![F(x) = [v]\limits^{v^\frac{1}{3}}_9](https://tex.z-dn.net/?f=F%28x%29%20%3D%20%5Bv%5D%5Climits%5E%7Bv%5E%5Cfrac%7B1%7D%7B3%7D%7D_9)
Expand

The density function of the volume F(v) is:

Differentiate F(x) to give:




So:

Yo sup??
Area of trapezium=1/2*(sum of opposite sides)*(height of trapezium)
=1/2*(12.5+17.5)*6
=1/2*30*6
=90 cm²
Therefore the correct answer is option A
Hope this helps.
Based from the graph, I think the answer is D. a piece-wise function with separate pieces of linear and step-functions. This is because as you can see from the graph, for intervals [0,1], [5,6], and [10,11] the function is linear. On the other hand, for the remaining intervals, it has a constant value which can be described as a step function.
I'll go with graphing cause when you try graphing a picewise function for example it's much harder to graph because it's to many numbers and you can't figure out what to graph especially for me.) mark me brainliest please