Pls help this is really important

Find the volume of a cone with a height of 11 cm and a base radius of 6 cm. Use the value 3.14 for n, and do not do rounding. Be

mrs_skeptik [129]

Given:

The cone with radius 6 cm and height 11cm.

Required:

Find the volume of a cone.

Explanation:

The formula for volume of cone:

$V=\frac{1}{3}\pi r^2h$

We have radius = 6 cm and height = 11 cm.

So,

$\begin{gathered} V=\frac{1}{3}\times3.14\times6^2\times11 \\ V=414.48cm^3 \end{gathered}$

Answer:

Volume of cone equals 414.48 cm cube.

7 0

1 year ago

Erica can run 1/6 start fraction, 1, divided by, 6, end fraction of a mile in a minute. Her school is \dfrac23 3 2 start

EastWind [94]

Her school is 2/3 miles away

2/3=4/6miles

So we need to find out how long it will take for her to run home from school...

School=4/6 miles

In 1 minutes she can run 1/6 miles

1min=1/6miles

In 2 minutes she can run 1/6+1/6 miles (1/6+1/6=2/6)

2min=2/6miles

3min=3/6miles

4min=4/6miles

It will take Erica 4 minutes to run 4/6 miles, so it'll take her 4 minutes to get home.

4 0

4 years ago

Read 2 more answers

What are the numbers of the symbol π

Andrews [41]

Answer:

i assume that is pi

Step-by-step explanation:

3.14159 is the first didgits, but a lot of my teachers just like to round it to 3.14

hope this helps :)

7 0

3 years ago

Read 2 more answers

A 12 ft ladder leans against a wall so that the base of the ladder is 5 ft from the wall How high, to the nearest foot, up on th

SSSSS [86.1K]

Answer: 10.9, about 11 ft

Step-by-step explanation:

a^2 + b^2 = c^2

a^2 + (5)^2 = (12)^2

3 0

3 years ago

Read 2 more answers

write an equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

dimaraw [331]

The equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is $y - 3 = \frac{-7x}{2}+ \frac{21}{4}$

<h3>Solution:</h3>

Given that we have to write equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

Let us first find the slope of given line AB

The slope "m" of the line is given as:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Here the given points are A(-2,2) and B(5,4)

$\text {Here } x_{1}=-2 ; y_{1}=2 ; x_{2}=5 ; y_{2}=4$

$m=\frac{4-2}{5-(-2)}=\frac{2}{7}$

Thus the slope of line with given points is $\frac{2}{7}$

We know that product of slopes of given line and slope of line perpendicular to given line is always -1

$\begin{array}{l}{\text {slope of given line } \times \text { slope of perpendicular bisector }=-1} \\\\ {\frac{2}{7} \times \text { slope of perpendicular bisector }=-1} \\ \\{\text {slope of perpendicular bisector }=\frac{-7}{2}}\end{array}$