I need more info that’s not
.01 is the answer to that or one one hundredth
Given:
1st term = 11
common difference = 6
f(x) = 11 + 6(x - 1)
f(18) = 11 + 6(18-1)
f(18) = 11 + 6(17)
f(18) = 11 + 102
f(18) = 113 number of seats in row 18.
Row
<span>
<span>
</span><span><span>
1 11 11
</span><span>2 11 6 17
</span>
<span>
3 17 6
23
</span>
<span>
4 23 6 29
</span>
<span>
5 29 6 35
</span>
<span>
6 35 6
41
</span>
<span>
7 41 6 47
</span>
<span>
8 47 6 53
</span>
<span>
9 53 6 59
</span>
<span>
10 59 6
65
</span>
<span>
11 65 6 71
</span>
<span>
12 71 6
77
</span>
<span>
13 77 6
83
</span>
<span>
14 83 6
89
</span>
<span>
15 89 6 95
</span>
<span>
16 95 6
101
</span>
<span>
17 101
6
107
</span>
<span>
18 107
6 113
</span></span></span>
Answer:
P(A|D) and P(D|A) from the table above are not equal because P(A|D) = and P(D|A) =
Step-by-step explanation:
Conditional probability is the probability of one event occurring with some relationship to one or more other events
.
P(A|D) is called the "Conditional Probability" of A given D
P(D|A) is called the "Conditional Probability" of D given A
The formula for conditional probability of P(A|D) = P(D∩A)/P(D)
The formula for conditional probability of P(D|A) = P(A∩D)/P(A)
The table
↓ ↓ ↓
: C : D : Total
→ A : 6 : 2 : 8
→ B : 1 : 8 : 9
→Total : 7 : 10 : 17
∵ P(A|D) = P(D∩A)/P(D)
∵ P(D∩A) = 2 ⇒ the common of D and A
- P(D) means total of column D
∵ P(D) = 10
∴ P(A|D) =
∵ P(D|A) = P(A∩D)/P(A)
∵ P(A∩D) = 2 ⇒ the common of A and D
- P(A) means total of row A
∵ P(A) = 8
∴ P(D|A) =
∵ P(A|D) =
∵ P(D|A) =
∵ ≠
∴ P(A|D) and P(D|A) from the table above are not equal
Step-by-step explanation:
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