Answer:
<em>The velocity of the truck is 3.33 m/s</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum
</u>
The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is
P=mv.
If we have a system of bodies, then the total momentum is the sum of the individual momentums:

If some collision occurs, the velocities change to v' and the final momentum is:

In a system of two masses:

There are two objects: The m1=4000 Kg car and the m2=6000 Kg truck. The car was moving initially at v1=4 m/s and the truck was at rest v2=0. After the collision, the car moves at v1'=-1 m/s. We need to find the velocity of the truck v2'. Solving for v2':

Substituting:



The velocity of the truck is 3.33 m/s
Punching a bag is a suitable example of the situation when the force applied to change shape of an object.
Given:
Shaft Power, P = 7.46 kW = 7460 W
Speed, N = 1200 rpm
Shearing stress of shaft,
= 30 MPa
Shearing stress of key,
= 240 MPa
width of key, w = 
d is shaft diameter
Solution:
Torque, T = 
where,

= 59.365 N-m
Now,


d = 0.0216 m
Now,
w =
=
= 5.4 mm
Now, for shear stress in key
= 
we know that
T =
= F. 
⇒
= 
⇒
= 
length of the rectangular key, l = 4.078 mm