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2 years ago

What voltage is required to move 6A through 5Ω?

Physics

1 answer:

Scorpion4ik [409]2 years ago

7 0

30 volts

E= IxR

See ohms law calculator image below

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A little girl riding a train rolls a ball toward the back of the train at 1.25 m/s NE. The train is traveling at a velocity of 1

Lelechka [254]

Answer:

Answer: 2.70m/s NE

Explanation:

Just did it.

4 0

3 years ago

Air escaping out from an air hose at a gas station always feels cool. Why?

kati45 [8]

Answer:

The air is contained at a high pressure in the tube. When it escapes from a small orifice, it suddenly expands. A large amount of its heat is absorbed in the process of expansion resulting in considerable fall in its temperature. This is why the escaping air feels cold.

8 0

1 year ago

Engineers are designing a curved section of a highway. If the radius of curvature of the curve is 194 m, at what angle should th

Brums [2.3K]

Answer:

The banking angle is 23.84 degrees.

Explanation:

Given that,

Radius of the curve, r = 194 m

Speed of the car, v = 29 m/s

On the banked curve, the centripetal force is balanced by the force of friction such that,

$mg\ tan\theta=\dfrac{mv^2}{r}$

$tan\theta=\dfrac{v^2}{rg}$

$tan\theta=\dfrac{(29)^2}{194\times 9.8}$

$\theta=23.84^{\circ}$

So, the banking angle is 23.84 degrees. Hence, this is the required solution.

5 0

2 years ago

In a race, you run 3000 meters east in 21 minutes. What is your velocity in km/min?

STALIN [3.7K]

velocity = distance / time v= d/t firstly you change 3000 m into km distance D = 3000/1000 = 3 km secondly time t = 21 min using velocity formula v = d/t = 3 km/21min =0.142km/min

6 0

2 years ago

An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s 1045 rad/s ). If a particular disk is

Scilla [17]

Answer:

The magnitude of the average angular acceleration of the disk is $4139.74\ rad/s^2$ .

Explanation:

Given that,

Angular velocity, $\omega_i=968.7\ rad/s$

The disk comes to rest, $\omega_i=0$

Time, t = 0.234 s

We need to find the magnitude of the average angular acceleration of the disk. It is given by change in angular velocity per unit time. So,

$\alpha =\dfrac{\omega f}{t}\\\\\alpha =\dfrac{968.7\ rad/s}{0.234\ s}\\\\\alpha =4139.74\ rad/s^2$

So, the magnitude of the average angular acceleration of the disk is $4139.74\ rad/s^2$ .

5 0

2 years ago