The ramp does 480J of useful work with an efficiency of 80% .
<h3>What is efficiency of work done ?</h3>
- Efficiency is the ratio of the useful energy released by a system to the input energy .
- Mathematically, efficiency of energy = out put energy/ input energy
<h3>
What is the useful work done by the ramp having efficiency 80% and an input work done 600J?</h3>
- The efficiency =output work done/ input work done
- 80% =output work done/ 600J
- output work done =( 80×600)/100
=480J
Thus, we can conclude that the useful work done by the ramp is 480J.
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Answer:
a. 3 m/s
Explanation:
The magnitude of the momentum of an object is given by:
where
m is the mass of the object
v is the speed of the object
For the ball in this problem, we know:
p = 12 kg m/s is the momentum
m = 4 kg is the mass
Solving the equation for v, the speed, we find:
Characteristics help us to classify seeds because different plants have different features.
<h3>How are characteristics used to identify and classify plants?</h3>
The divisions classify plants that are based on whether they reproduce by spores or seeds. Spore-bearing plants include ferns, club mosses, and horsetail while on the other hand, Seed-bearing plants are divided into gymnosperms and angiosperms. Different plants have different characteristics and features so on the basis of these characteristics we can easily classify seeds whether they belong from angiosperm and gymnosperm.
So we can conclude that characteristics help us to classify seeds because different plants have different features.
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Answer:
a) T = 2838.6 N, b) W = 1003.2 J, c) W = 6.22 10⁴ J, d) W = 2.79 10³ J
e) v_f = 2.65 m / s
Explanation:
a) To find the tension of the cable let's use Newton's second law
T - W = m a
T = W + ma
T = m (g + a)
let's calculate
T = 285 (-9.8 - 0.160)
T = 2838.6 N
b) net work is stress work minus weight work
W = F d
W = (T-W) d
W = (m a) d
W = (285 0.160) 22
W = 1003.2 J
c) the work done by the cable
W = T d cos 0
W = 2838.6 22.0
W = 6.22 10⁴ J
d) The work done by the weight
the displacement is upwards and the weight points downwards, so the angle is 180º
W = F. d
W = F d cos 180
W = -285 22.0
W = 2.79 10³ J
e) the final speed of the load. Let's use the relationship between work and the change in kinetic energy
W = ΔK
as part of rest K₀ = 0
W = ½ m v_f²
v_f =
v_f =
v_f = 2.65 m / s
A plane electromagnetic wave of frequency 20 GHz moves in the positive y-axis direction such that its electric field is pointed along the z-axis. The amplitude of the electric field is 10 V/m. The start of time is chosen so that at t
When an electric field interacts with a magnetic field, electromagnetic waves are created. Therefore, they are referred to as "electromagnetic" waves. An electromagnetic wave's electric field and magnetic field are perpendicular to one another (at right angles).
An electromagnetic spectrum is a group of waves with similar characteristics to electromagnetic waves. All electromagnetic waves are transverse waves, capable of moving through a vacuum, and moving at the same speed in a vacuum, which is 300,000,000 times the speed of light.
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