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Liono4ka [1.6K]
3 years ago
5

A seamstress has 1/4 of a foot of thread. Then she uses 1/5 of a foot of thread to sew a hole. How much of the thread is left?

Mathematics
1 answer:
Ilya [14]3 years ago
3 0
Answer is <span>C) 1/20 of a foot

1/4 -1/5
= 5/20 - 4/20
=1/20</span>
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The value of a car bought new for $28900 decreases 15% each year. Identify the function for the value of the car. Does the funct
Eva8 [605]

Answer:

<u>V (t) = 28,900 - 4,335t</u>

<u>The function clearly represent a decay</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Value of the car = $ 28,900

Annual depreciation = 15% = 0.15

2. Identify the function for the value of the car. Does the function represent growth or decay?

Let y represent the value of the car after t years of utilization, let p the price of the car and d, the annual depreciation, therefore:

V (t) = p - (d * t * p)

Replacing with the values we know:

V (t) = 28,900 - (0.15 * t * 28.900)

V (t) = 28,900 - (0.15 * t * 28.900)

<u>V (t) = 28,900 - 4,335t</u>

<u>The function clearly represent a decay.</u>

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Chuge%7B%5Cgreen%7D%5Cfcolorbox%7Bblue%7D%7Bcyan%7D%7B%5Cbf%7B%5Cunderline%7B%5Cred%7B%5C
MariettaO [177]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's find out the gradient (Slope " m ") of line q ;

\qquad \sf  \dashrightarrow \:m = \dfrac{y_2 - y_1}{x_2 - x_1}

\qquad \sf  \dashrightarrow \:m = \dfrac{4 - 0}{0 - 1}

\qquad \sf  \dashrightarrow  \:m =  - 4

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :

\qquad \sf  \dashrightarrow \:y - 4 = m(x - 0)

\qquad \sf  \dashrightarrow \:y = mx + 4

Now, plug in the value of gradient ~

\qquad \sf  \dashrightarrow \:y =  - 4x + 4

here we can clearly observe that, the Area under the curve can easily be represented as :

\qquad \sf  \dashrightarrow \:y <  - 4x + 4

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

5 0
2 years ago
Find the measure of HG¯¯¯¯¯¯¯¯.<br> A. 12<br> B. 16<br> C. 14<br> D. 7
Paraphin [41]

HG^2 = FG * (FG + EF)

Fill in the values:

(x+3)^2 = x * (7+x)

Simplify the right side:

(x+3)^2 = 7x +x^2

Rewrite the left side using the FOIL method

x^2 + 6x + 9 = 7x +x^2

Subtract x^2 from both sides:

6x +9 = 7x

Subtract 6x from both sides:

x = 9

Now you have x solve for HG

HG = x +3 = 9+3 = 12

The answer is A.

3 0
3 years ago
Identify whether the equation represents an exponential growth or exponential decay function.1. y = 1/4 (1/e)^-2x2. y = (1/e)^4x
zvonat [6]

The general formula for exponential growth and decays is:

y=y_0e^{kx}

if k>0 then then it is an exponential growth function. If k<0 then the function represents an exponential decay.

Now we need to classify each of the functions:

1.

The function

y=\frac{1}{4}(\frac{1}{e})^{-2x}

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\begin{gathered} y=\frac{1}{4}(e^{-1})^{-2x}^{} \\ =\frac{1}{4}e^{2x} \end{gathered}

comparing with the general formula we notice that k=2, therefore this is an exponential growth.

2.

The function

y=(\frac{1}{e})^{4x}

can be written as:

\begin{gathered} y=(\frac{1}{e})^{4x} \\ y=(e^{-1})^{4x} \\ y=e^{-4x} \end{gathered}

comparing with the general formula we notice that k=-4, therefore this is an exponential decay.

3.

The function

y=2e^{-x}+1

comparing with the general formula we notice that k=-1, therefore this is an exponential decay.

5 0
1 year ago
I am confused on how to get the answer
Ksju [112]

Answer:

try using this

Step-by-step explanation:

multiply  π  which = 3.14 by the diamiter so it would be 3.14 x 6.5 = 20.41

4 0
3 years ago
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