<h2>Answer : 1 is gamma, 2 is alpha and 3 is beta radiations.</h2><h3>Explanation :</h3>
In the given information all the radiations were stopped by the lead block, if we assume that first radiations were gamma radiation, as they were not stopped by the cloth whereas all other radiations were stopped.
In second case, aluminum foil and wood were able to block alpha and beta radiations. Whereas, paper was used to stop the alpha particles but not the gamma and beta rays. And then a thick concrete stopped all the radiations.
This clarifies that the first radiation are gamma rays, second is alpha rays and third is beta rays.
Answer: The wire is still copper and does not change by cutting it
Explanation:
Democritus postulated that all materials were composed of these tiny particles called as "atomos".
Daltons postulates are:.
1. All matter is made of very tiny particles called atoms.
2. Atoms is indivisible.
3. Atoms of a given element are identical in mass and chemical properties.
4. Atoms of different elements have different masses and chemical properties.
5. Atoms combine in the ratio of small whole numbers to form compounds.
6. The relative number and kinds of atoms are constant in a given compound.
Thus when copper wire is cut into the smallest possible pieces, the atoms were intact as they are indivisible and all atoms have same mass and chemical properties.Thus the wire is still copper and does not change by cutting it
Answer:
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Explanation:
Robert Hooke Anton van leeuwenhoek
- He was the first to use the word cell. - He observed animacules.
- he observed cork cells. - He used polishes lens.
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Answer:
12 liters of oxygen are released from the decomposition of the peroxide.
Explanation:
The hydrogen peroxide is decomposed by this reaction:
2 H₂O₂ (l) → 2 H₂O (l) + O₂ (g)
Molar mass H₂O₂ = 34 g/m
Moles of peroxide: 36.5 g / 34 g/m = 1.07 moles
Ratio is 2:1, so 2 moles of peroxide will be decomposed in 1 mol of oxygen (exactly the half)
1.07 moles of peroxide will be decomposed in the half of moles, 0.54 moles
Let's apply the Ideal Gases law Equation to solve the volume
1 atm . V = 0.54 mol . 0.082 .273K
V = (0.54 mol . 0.082 .273K) / 1 atm → 12L