The element from those four that is a noble gas is krypton.
Answer:
products
Explanation:
In chemistry, chemical reactions is the combination of two or more substances to yield other substances. The substances that react is called REACTANTS while the substances formed after the reaction is called PRODUCTS.
According to this question, a mixture of oxygen and hydrogen is ignited in a test tube as follows:
Hydrogen + Oxygen → Water + Energy
In this reaction, the substances being combined (usually found on the left side of the equation) are hydrogen and oxygen. Hence, oxygen and hydrogen are REACTANTS. Also, the substances produced as a result of the reaction is water (H2O). The PRODUCTS of the reaction is WATER.
Answer:
1. The length of the wire is halved.
the resistance of a conductor is directly proportional to it's length (L) as R - L. Thus doubling it's length will double it's resistance, while halving it's length would halve the resistance. Also the resistance of a conductor is inversely proportional to it's cross sectional area.
2. The area of cross-section of the conductor in increased.
On increasing the area of cross-section, resistance decreases. Thus is because resistance is inversely proportional to area.
3. The temperature of the conductor is increased.
With increasing temperature, the resistance of the wire increases as collisions within the wire increases and "slow" the flow of current... Since conductors typically display an increased resistivity with temperature increase, they have a positive temperature coefficient.
Answer:
Explanation:
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Step 1: Write Imbalance Equation
CH₃CHO + O₂ → CO₂ + H₂O
Step 2: Balance Carbon Atoms:
There are 2 carbon atoms at reactant side and one at product side. So multiply CO₂ with 2 to balance them. i.e.
CH₃CHO + O₂ → 2 CO₂ + H₂O
Step 3: Balance Hydrogen Atoms:
There are 4 hydrogen atoms at reactant side and 2 Hydrogen atoms at product side. So, multiply H₂O by 2 to balance Hydrogen on both sides. i.e.
CH₃CHO + O₂ → 2 CO₂ + 2 H₂O
Step 4: Balance Oxygen Atoms:
There are 3 Oxygen atoms at reactant side and 6 Oxygen atoms at product side. In order to balance them multiply O₂ on reactant side by 2.5 (5/2). i.e
CH₃CHO + 5/2 O₂ → 2 CO₂ + 2 H₂O
Step 6: Eliminate Fraction:
Multiply overall equation by 2 to eliminate fraction. i.e.
2 CH₃CHO + 5 O₂ → 4 CO₂ + 4 H₂O
