<span>c. Real gases and fusion reactions </span>
Force = mass * acceleration
= 14 * 2 = 28N
Work done (energy) = Force * distance
= 28 * 5 = 140J
Answer:
the % yield is 82%
Explanation:
Given the data in the question,
we know that;
Molar mass of benzil is 210.23 g·mol−1
Molar mass of dibenzyl ketone is 210.27 g·mol−1
Molar mass of tetraphenylcyclopentadienone is 384.5 g·mol−1
Now,
2.0 g benzil = 2 g / 210.23 g·mol−1 = 0.0095 mole
2.2 g dibenzyl ketone = 2.2 / 210.27 = 0.0105 mole
3.0 g of tetraphenylcyclopentadienone = 3 / 384.5 = 0.0078 mole
Now, the limiting reagent is benzil. 0.0095 mole can reacts wiyh 0.0095 mole of dibenzyl ketone
percentage yield = ( 0.0078 mole / 0.0095 mole ) × 100%
= 0.82 × 100%
= 82%
Therefore, the % yield is 82%
Answer: The final temperature of the system will be 
Explanation:
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of steam = 25 g
= mass of water = 0.2384 kg = 238.4 g (1kg=1000g)
= final temperature = ?
= temperature of steam = 
= temperature of water = 
= specific heat of steam = 
= specific heat of water= 
Now put all the given values in equation (1), we get
![25g\times 1.996J/g^0C\times (T_{final}-116)=-[238.4g\times 4.184J/g^0C\times (T_{final}-8)]](https://tex.z-dn.net/?f=25g%5Ctimes%201.996J%2Fg%5E0C%5Ctimes%20%28T_%7Bfinal%7D-116%29%3D-%5B238.4g%5Ctimes%204.184J%2Fg%5E0C%5Ctimes%20%28T_%7Bfinal%7D-8%29%5D)
Therefore, the final temperature of the system will be
