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Marina86 [1]
4 years ago
14

03 is an example of a what?

Chemistry
1 answer:
Leto [7]4 years ago
3 0
I'm not sure what the question is but 3 is an example of a prime number. I hope this help
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What is the most complete answer below about the information, found about the element uranium in the periodic table
jonny [76]

Answer:

92 is that atomic number and 238.03 is the atomic mass number

Explanation:

The structure of the atom is given as:

                    ⁹²₂₃₈.₀₃U

The number 92 is the atomic number of the atom.

  The atomic number is the number of protons within an atom. This number defines the nature and type of atom that we have.

238.03 is the atomic mass number;

  The is the number of protons and neutrons within an atom. It is typically the mass of nucleus.

6 0
3 years ago
Match the following.
cupoosta [38]
1.icosahedralb2.helicalc3.complexa
8 0
3 years ago
You use energy to heat your home. What ultimately happens to the energy that you pay for in your heating bill?
Alekssandra [29.7K]

Answer:

1. The energy escapes your home and heats the outside.

Explanation:

4 0
4 years ago
_____ compounds include a prefix on the first and second elements and a suffix on the second element, whereas _____ compounds do
Anit [1.1K]

Answer:

Molecular compound and ionic compound

Explanation:

Molecular compounds include a prefix on the first and second elements and a  suffix on the second element, whereas Ionic compounds do not have prefixes and only include a suffix on the second element.

4 0
3 years ago
Calculate the molarity of sodium chloride in a half-normal saline solution (0.45% NaCl). The molar mass of NaCl is
Rus_ich [418]

Answer:

0.077 M

Explanation:

Data Given :

The concentration of half normal (NaCl) saline = 0.45g / 100 g

So,

Volume of Solution = 100 g = 100 mL

Volume of Solution in Liter = 100 mL / 1000

Volume of Solution = 0.1 L

molar mass of NaCl = 58.44 g/mol

Molarity:

Molarity is the representation of the solution. It is amount of solute in moles per liter of solution and represented by M

Formula used for Molarity

                M = moles of solute / Liter of solution . . . . . . . . . . (1)

Now to find number of moles of Nacl

                no. of moles of NaCl = mass of NaCl / molar mass

                no. of moles of NaCl = 0.45g / 58.44 g/mol

               no. of moles of NaCl = 0.0077 g

Put values in the eq (1)

                  M = moles of solute / Liter of solution . . . . . . . . . . (1)

                  M = 0.0077 g / 0.1 L

                  M = 0.077 M

So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M

3 0
3 years ago
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