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sertanlavr [38]
3 years ago
5

PLZ HELP I really need help with this.

Mathematics
1 answer:
kvv77 [185]3 years ago
3 0

Answer:

x = \frac{mp + e}{t}

Step-by-step explanation:

times p on both sides

then plus e on both sides

then divide t on both sides

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timofeeve [1]
1. 25
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3 years ago
Geometry question need help finding the answer.
Xelga [282]

Answer: 1208.96

Step-by-step explanation:

The volume of the cylinder is (\pi)(4^2)(4)=64\pi

The volume of the prism is (6)(12)(14)=1008

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6 0
1 year ago
find the equation of the circle where (-9,4),(-2,5),(-8,-3),(-1,-2) are the vertices of an inscribed square.
solniwko [45]
Check the picture below, so, that'd be the square inscribed in the circle.

so... hmm the diagonals for the square are the diameter of the circle, and keep in mind that the radius of a circle is half the diameter, so let's find the diameter.

\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ -2}}\quad ,&{{ 5}})\quad &#10;%  (c,d)&#10;&({{ -8}}\quad ,&{{ -3}})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}&#10;\\\\\\&#10;\stackrel{diameter}{d}=\sqrt{[-8-(-2)]^2+[-3-5]^2}&#10;\\\\\\&#10;d=\sqrt{(-8+2)^2+(-3-5)^2}\implies d=\sqrt{(-6)^2+(-8)^2}&#10;\\\\\\&#10;d=\sqrt{36+64}\implies d=\sqrt{100}\implies d=10

that means the radius r = 5.

now, what's the center?  well, the Midpoint of the diagonals, is really the center of the circle, let's check,

\bf \textit{middle point of 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ -2}}\quad ,&{{ 5}})\quad &#10;%  (c,d)&#10;&({{ -8}}\quad ,&{{ -3}})&#10;\end{array}\qquad &#10;\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{-8-2}{2}~,~\cfrac{-3+5}{2} \right)\implies (-5~,~1)

so, now we know the center coordinates and the radius, let's plug them in,

\bf \textit{equation of a circle}\\\\ &#10;(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2&#10;\qquad &#10;\begin{array}{lllll}&#10;center\ (&{{ h}},&{{ k}})\qquad &#10;radius=&{{ r}}\\&#10;&-5&1&5&#10;\end{array}&#10;\\\\\\\&#10;[x-(-5)]^2-[y-1]^2=5^2\implies (x+5)^2-(y-1)^2=25

8 0
3 years ago
Which angles are complementary?
Law Incorporation [45]
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3 0
2 years ago
Solve this equation<br>5(-7x-3)- 8x=-230​
Brut [27]

Simplifying

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Reorder the terms:

5(-3 + 7x) = 230

(-3 * 5 + 7x * 5) = 230

(-15 + 35x) = 230

Solving

-15 + 35x = 230

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '15' to each side of the equation.

-15 + 15 + 35x = 230 + 15

Combine like terms: -15 + 15 = 0

0 + 35x = 230 + 15

35x = 230 + 15

Combine like terms: 230 + 15 = 245

35x = 245

Divide each side by '35'.

x = 7

Simplifying

x = 7

5 0
3 years ago
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