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3 years ago

Sum of 500 consecutive integers is 250 . what is the product same 500 numbers

Mathematics

1 answer:

saw5 [17]3 years ago

3 0

Answer:

250 and 2 because i think 250 multiply by 2 is 500

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The tape diagram models the lengths of two snowboarding trails. The expert trail is 750 meters longer than the beginner trail. H

Kay [80]

Answer:

In a tape diagram, each of the lengths represents a fixed quantity of something.

Let's suppose that each one of these lengths represents a distance d.

We also know that the expert trail is 750 meters longer than the beginner one.

And in the tape diagram, the expert trail has 3 more lengths than the beginner trail, then we must have that the difference in distance must be equivalent with the difference in lengths.

750m = 3*d

d = 750m/3 = 250m

Then each length in the tape diagram represents 250m

With this we can find the length of each trail.

The beginner trail has 1 length, then it is 1*250m = 250 meters long.

The expert trail has 4 lengths, then it is 4*250m = 1000 meters long.

5 0

2 years ago

The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding

Andru [333]

Answer:

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Step-by-step explanation:

Values (x) ∑(Xi-X)^2

----------------------------------

29.1 0.1702

28.5 1.0252

28.8 0.5077

29.4 0.0127

29.8 0.0827

30.1 0.3452

30.6 1.1827

----------------------------------------

236.1 3.4088

Mean = 236.1 / 8 = 29.51

$S_{x}=\sqrt{3.4088/(8-1)}=0.6978$

Statement of the null hypothesis:

H0: u ≥ 30 the mean wedding cost is not less than $30,000

H1: u < 30 the mean wedding cost is less than $30,000

Test Statistic:

$t=\frac{X-u}{S/\sqrt{n}}=\frac{29.51-30}{0.6978/\sqrt{8}}= \frac{-0.49}{0.2467}=-1.9861$

Test criteria:

SIgnificance level = 0.05

Degrees of freedom = df = n - 1 = 8 - 1 = 7

Reject null hypothesis (H0) if

$t$

Finding in the t distribution table α=0.05 with df=7, we have

$t_{0.05,7}=2.365$

$t>-t_{0.05,7}$ = -1.9861 > -2.365

Result: Fail to reject null hypothesis

Conclusion: Do no reject the null hypothesis

u ≥ 30 the mean wedding cost is not less than $30,000

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Hope this helps!

5 0

3 years ago