The question is incomplete, the complete question is:
A chemist prepares a solution of vanadium (III) chloride (VCl3) by measuring out 0.40g of VCl3 into a 50.mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of Cl− anions in the chemist's solution. Be sure your answer is rounded to the correct number of significant digits.
Answer:
0.153M of anions
Explanation:
First we calculate the concentration of the solution. From m/M= CV
m=given mass, M= molar mass, C =concentration of solution, V= volume of solution
Molar mass of compound= 51 + 3(35.5)= 157.5gmol-1
0.4g/157.5gmol-1= C×50/1000
C= 2.54×10-3/0.05= 0.051M
But 1 mole of VCl3 contains 3 moles of anions
Therefore, 0.051M will contain 3×0.051M of anions= 0.153M of anions
Answer:
there are no questions but hit me up if ya need me (discordAkashTheMissle07#3880)
Explanation:
Answer: B) metals, non-metals, metalloids
An example of a metal is iron. A non-metal example is oxygen, which is a gas at STP (standard temperature and pressure).
A metalloid is a bit of a mix between a metal and non-metal element. It's sorta like an element that has both properties of metals and non-metals, or it's in a murky gray area. An example of a metalloid would be silicon.
I think the best answer among your choices is letter D. at the particles loses energy, they move closer together and more attraction are able to form. Due to the low temperature, the energy in the particles looses there energy and some point they will solidify or the space between particles will decrease