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3 years ago

The following is an example of which type of chemical reaction?Na (s) + H2O (l) Imported Asset NaOH (aq) + H2 (g)

Chemistry

2 answers:

Llana [10]3 years ago

7 0

Answer:

This reaction is a single replacement reaction.

Explanation:

Step 1: Data given

A single-replacement reaction is a reaction in which one element replaces a similar element in a compound. The general form of a single-replacement (also called single-displacement) reaction is:

A+BC→AC+B

A decomposition reaction is a reaction in which a compound breaks down into two or more simpler substances. The general form of a decomposition reaction is:

AB→A+B

A double-replacement reaction is a reaction in which the positive and negative ions of two ionic compounds exchange places to form two new compounds. The general form of a double-replacement (also called double-displacement) reaction is:

AB+CD→AD+BC

A combustion is a high-temperature exothermic (heat releasing) redox (oxygen adding) reaction between a fuel and an oxidant, usually atmospheric oxygen.

Whenever we complete a combustion reaction of a hydrocarbon (compound of C and H) we generally have the same products formed: CO2 and H2O.

Na (s) + H2O (l) → NaOH (aq) + H2 (g)

This reaction is not a decomposition because we don't break down a compound.

This reaction is not a combustion because we don't oxidze a compound to form CO2 and H2O

This reaction is a replacement reaction. But only a single replacement reaction because one element replaces a similar element in a compound

lora16 [44]3 years ago

4 0

Answer:

The answer to your question is Single replacement

Explanation:

Data

Chemical reaction

Na + H₂O ⇒ NaOH + H₂

Single replacement is a chemical reaction in which a metal replaces the cation of a compound.

Decomposition is a chemical reaction in which a compound forms 2 or more products.

Double replacement in this chemical reaction two compounds react interchanging their cations and anions.

Combustion in this chemical reaction the reactants must be a compound with carbon and the other oxygen and the products must be carbon dioxide and water.

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Define and describe each of the following forms of energy and then classify each as either: potential energy, kinetic energy, or

TiliK225 [7]

Potential energy: It is an energy stored in an object due to its position.

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Electric energy: Energy due to flow of charged particles. It is a type of a stored potential energy due to relative position of charged particle .

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Transfer of some quantity of energy:

Heat energy: Transfer or flow of energy from one object to another in form of heat. This transfer is due to difference in temperature of two objects.

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3 years ago

Read 2 more answers

A balloon filled with helium has a volume of 4.5 × 103 L at 25°C. What volume will the balloon occupy at 50°C if the pressure su

Tom [10]

Answer:

$V_2 = 4.87 * 10^3$

Explanation:

This question is an illustration of ideal Gas Law;

The given parameters are as follows;

Initial Temperature = 25C

Initial Volume = 4.5 * 10³L

Required

Calculate the volume when temperature is 50C

NB: Pressure remains constant;

Ideal Gas Law states that;

$PV = nRT$

The question states that the pressure is constant; this implies that the constant in the above formula are P, R and n

Divide both sides by PT

$\frac{PV}{PT} = \frac{nRT}{PT}$

$\frac{V}{T} = \frac{nR}{P}$

Represent $\frac{nR}{P}$ with k

$\frac{V}{T} = k$

$k = \frac{V_1}{T_1} = \frac{V_2}{T_2}$

At this point, we can solve for the required parameter using the following;

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$

Where V1 and V2 represent the initial & final volume and T1 and T2 represent the initial and final temperature;

From the given parameters;

V1 = 4.5 * 10³L

T1 = 25C

T2 = 50C

Convert temperatures to degree kelvin

V1 = 4.5 * 10³L

T1 = 25 +273 = 298K

T2 = 50 + 273 = 323K

Substitute values for V1, T1 and T2 in $\frac{V_1}{T_1} = \frac{V_2}{T_2}$

$\frac{4.5 * 10^3}{298} = \frac{V_2}{323}$

Multiply both sides by 323

$323 * \frac{4.5 * 10^3}{298} = \frac{V_2}{323} * 323$

$323 * \frac{4.5 * 10^3}{298} = V_2$

$V_2 = 323 * \frac{4.5 * 10^3}{298}$

$V_2 = \frac{323 * 4.5 * 10^3}{298}$

$V_2 = \frac{1453.5 * 10^3}{298}$

$V_2 = 4.87 * 10^3$

Hence, the final volume at 50C is $V_2 = 4.87 * 10^3$

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