Because displacement of water is the convenient way to obtain gas.
Answer:
357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine
Explanation:
In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.
Given mass of sample compound = 630 g
Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;
56.7 % = 56.7/100 = 0.567
Mass of transition metal = 0.567 * 630 = 357.21 g
Therefore, the mass of the transition metal present in 630 g of the compound is approximately 357 g
Answer:
Here's what I get
Explanation:
At the introductory level of chemistry, I can think of only two situations when you use Greek prefixes.
They indicate the number of atoms or groups in a molecule when you are naming a compound.
1. Binary covalent compounds
For example, P₂S₅ is diphosphorus pentasulfide.
2. Hydrates
For example, Na₂SO₄·10H₂O is sodium sulfate decahydrate.
Answer: $0.48
Explanation: $1.60×0.30= 0.48
