The expression in scientific notation is given as follows:
3.5 x 10³.
<h3>What is scientific notation?</h3>
A number in scientific notation is given by:
![a \times 10^b](https://tex.z-dn.net/?f=a%20%5Ctimes%2010%5Eb)
With the base being
.
For this problem, the expression is given by:
![\frac{5 \times 10^2 \times 4.2 \times 10^4}{6 \times 10^3}](https://tex.z-dn.net/?f=%5Cfrac%7B5%20%5Ctimes%2010%5E2%20%5Ctimes%204.2%20%5Ctimes%2010%5E4%7D%7B6%20%5Ctimes%2010%5E3%7D)
When two factors of a multiplication have the same base and different exponent, we <u>keep the base and add the exponents,</u> hence:
![10^2 \times 10^4 = 10^6](https://tex.z-dn.net/?f=10%5E2%20%5Ctimes%2010%5E4%20%3D%2010%5E6)
5 x 4.2 = 21, hence the expression is:
![\frac{5 \times 10^2 \times 4.2 \times 10^4}{6 \times 10^3} = \frac{21 \times 10^6}{6 \times 10^3}](https://tex.z-dn.net/?f=%5Cfrac%7B5%20%5Ctimes%2010%5E2%20%5Ctimes%204.2%20%5Ctimes%2010%5E4%7D%7B6%20%5Ctimes%2010%5E3%7D%20%3D%20%5Cfrac%7B21%20%5Ctimes%2010%5E6%7D%7B6%20%5Ctimes%2010%5E3%7D)
When we divide two terms with the same base and different exponents, we keep the base and subtract the exponents, hence:
![\frac{21 \times 10^6}{6 \times 10^3} = 3.5 \times 10^3](https://tex.z-dn.net/?f=%5Cfrac%7B21%20%5Ctimes%2010%5E6%7D%7B6%20%5Ctimes%2010%5E3%7D%20%3D%203.5%20%5Ctimes%2010%5E3)
Which is the simplified expression.
More can be learned about scientific notation at brainly.com/question/16394306
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X| 1 | 15 | 225 |
y| 4 | ? | 900 |
![\dfrac{y}{x}=const.](https://tex.z-dn.net/?f=%5Cdfrac%7By%7D%7Bx%7D%3Dconst.)
therefore
[tex]\dfrac{4}{1}=4;\ \dfrac{900}{225}=4;\ \dfrac{?}{15}=4\to?=60[\tex]
Answer: ? = 60
Answer:
A
Step-by-step explanation:
Nonlinear would be any function where both values are not changing by some fixed amount. In B, f(x) increases by 1 for every time x increases by 1 so that's linear. For C, f(x) increases by 2 for every time x increases by 1, so that's linear. For D, f(x) increases by 3 for every time x increases by 1 so that's also linear. For A, f(x) does not always change by the same amount, so it's nonlinear.
Step-by-step explanation:
The snowplow's speed is 40 mph minus the loss from the snow, which is 1.2 mph times the depth of snow in inches.
y = 40 − 1.2x
When y = 0:
0 = 40 − 1.2x
1.2x = 40
x = 33 ⅓
The snowplow stops moving when the snow is 33 ⅓ inches deep or more.