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My name is Ann [436]
3 years ago
7

Kayla is painting a room that is 12 feet long and 12 feet wide. The ceiling in the room is 8 feet high. The cost of painting the

walls and door is $0.33 per square foot. The cost of painting the ceiling is $0.66 per square foot. Enter the cost, in dollars, for Kayla to paint the room.​
Mathematics
1 answer:
Fiesta28 [93]3 years ago
3 0

Answer: $221.76

Step-by-step explanation:

Each wall has a length of 12 and a height of 8 and there are 4 walls

(12 x 8) x 4 = 384 sq ft

multiply sq ft by cost ($0.33)

384 x 0.33 = $126.72 for the walls and door

The ceiling has a length of 12 and a width of 12

12 x 12 = 144 sq ft

multiply sq ft by cost ($0.66)

144 x 0.66 = 95.04

add the costs

126.72 + 95.04 = $221.76 total

image of drawing of room

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vekshin1

Answer:

1.20 + 1.40x ≥ 5, or $1.20 + $1.40x ≥ $5

Step-by-step explanation:

So since you are only buying 1 soda and you are buying multiple bags of Cheetos so you are able to use you debit card and meet the requirement of at least $5, you can make the inequality:

1.20 + 1.40x ≥ 5, or $1.20 + $1.40x ≥ $5

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3 years ago
What's a multiplication equation that corresponds to this division equation 10÷5​
soldier1979 [14.2K]

Answer:

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3 years ago
A coin is tossed four times What is the probability of getting four heads? (1 mark) a) b) What is the probability of getting exa
BlackZzzverrR [31]
<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

1/2\times1/2\times1/2\times1/2=1/16

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have 2^{4} or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = \frac{4!}{2!2!} = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = 1/2\times1/2\times1/2\times1/2=1/16

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = 1/16+1/16+1/16+1/16+1/16=5/16

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3 years ago
I need help asap please!!!
Mashcka [7]
1. x = 118      2. x = -54      3. x = -54      4. x = -54

5 0
4 years ago
Find two numbers whose sum is 44 and whose difference is 6.<br> smaller number<br> larger number
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X+ y = 44
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—————
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x = 25
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3 years ago
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