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Dmitriy789 [7]
3 years ago
5

Hurry plzzz

Mathematics
1 answer:
diamong [38]3 years ago
3 0

Step-by-step explanation:

  • 12x-4y=-8
  • y=3x+2
  • 12x-4(3x+2)=-8

12x-12x-8=-8

0=0

I think,no solution

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find the equation of a line that is parallel to the straight line 2x-y=-3 and crosses the x-axis at x=-5​
Alecsey [184]

Answer:

y=2x+10

Step-by-step explanation:

In line equations its helpful to write your line in the form y = ax + b. This helps because a is always the gadient of the line and b is always the y intercept.

In this case it is y=2x+3

All parallel lines have the same gradient. The gradient of this line = 2.

If the line crosses the x axis at x=-5, then when x =-5 y = 0.

If you put all this in the form y =ax + b you get 0 = 2(-5) +b

So all you need to do to find b is rearrange. b = 10.

Therefore your line has gradient 2 and y intercept 10.

y = 2x + 10

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timama [110]

Answer:

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Step-by-step explanation:

6 0
3 years ago
One zero of x^3-3x^2-6x+8=0 is -2. WHat are the other zeros of the function?
Irina18 [472]
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