Answer:

Step-by-step explanation:
<u>The full question:</u>
<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"</em>
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The permutation of choosing 3 members from a group of 11 would be:
P(n,r) = 
Where n would be the total [in this case n is 11] & r would be 3
Which is:
P(11,3) = 
So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:
1/990
Answer:
2
Step-by-step explanation:
0.4%×500=2
Hope it helps!!!
Answer:
Step-by-step explanation:
25/8
8*3=24
25-24=1
3 1/8
To find the answer to the question we do the equation
Which gets us our answer of 20%
ANSWER
Approximately after 15 minutes.
EXPLANATION
The growth rate of the first bacteria is

The growth rate of the first bacteria :

To find the time that, there will be an equal number of bacteria, we equate the two equation;



We solve for t to get,

Or

We discard the negative value.
This implies that,
