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lord [1]
3 years ago
15

Help plsssssss... 3C(s) + 2Fe2O3 (5) ► Fe

Chemistry
2 answers:
jek_recluse [69]3 years ago
7 0

Answer:

Single displacement.

Explanation:

This is because Iron (Fe) was "switched" with C and this being the only "switch" in the equation makes it a single displacement.

blondinia [14]3 years ago
6 0

Answer:

single displacement

Explanation:

the Fe was switched out with the C. they are the only ones that switched, making it a single displacement

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Under which conditions of temperature and pressure would a 1-liter sample of a real gas behave most like an ideal gas?
Sladkaya [172]

Answer : The correct option is (3) 500 K and 0.1 atm.

Explanation :

A real gas behaves ideally at high temperature and low pressure.

The ideal gas equation is,

PV=nRT

where,

P = pressure of gas

V = Volume of gas

R = Gas constant

T = temperature of gas

n = number of moles of gas

The ideal gas works properly when the inter-molecular interactions between the gas molecules and volume of gas molecule will be negligible. This is possible when pressure is low and temperature is high.

Therefore, the correct option is (3) 500 K and 0.1 atm.

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its an animal that preys on others

Explanation:

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2 years ago
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A combustion analysis of 5.214 g of a compound yields 5.34 g co 2 ​ , 1.09 g h 2 ​ o, and 1.70 g n 2 ​ . if the molar mass of th
nekit [7.7K]
Answer is: C₃H₃N₃O₃.
Chemical reaction: CₓHₓNₓOₓ + O₂ → aCO₂ + x/2H₂ + x/2N₂.
m(CₐHₓNₓ) = 5,214 g.
m(CO₂) = 5,34 g.
m(H₂) = 1,09 g.
m(N₂) = 1,70 g.
n(CO₂) = n(C) =  5,34 g ÷ 44 g/mol = 0,121 mol.
n(H₂O) = 1,09 g ÷18 g/mol = 0,06 mol.
n(H) = 2 · 0,0605 mol = 0,121 mol.
n(N₂) = 1,7 g ÷ 28 g/mol = 0,0607 mol.
n(N) = 0,0607 mol · 2 = 0,121 mol.
n(C) : n(H) : n(N) = 0,121 mol : 0,121 mol : 0,121 mol /: 0,121
n(C) : n(H) : n(N) = 1 : 1 : 1.
M(CHN) = 27 g/mol.
m(O₂) = 8,13 g - 5,214 g = 2,914 g.
n(O₂) = 2,914 g ÷ 32 g/mol = 0,09 mol.
n(CₓHₓNₓOₓ) = 5,214 g ÷ 129,1 g/mol = 0,0404 mol.
n(CₓHₓNₓOₓ) : n(CO₂) = 1 : 3.


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