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Montano1993 [528]
3 years ago
5

Write 0.000000093425 in Scientific Notation with 4 significant figures.

Chemistry
2 answers:
worty [1.4K]3 years ago
7 0

Answer:

9.343\times 10^{-8}

Explanation:

Scientific notation is the way of writing numbers which are either large or small. The number is written in the scientific notation when the number is between 1 and 10 and then multiplied by the power of 10.

The given number:

0.000000093425 can be written as 9.3425\times 10^{-8}

Answer upto 4 significant digits = 9.343\times 10^{-8}

Romashka-Z-Leto [24]3 years ago
6 0

<u>Answer:</u> The given number in scientific notation is 9.342\times 10^{-8}

<u>Explanation:</u>

Scientific notation is the notation where a number is expressed in the decimal form. This means that the number is always written in the power of 10 form. The numerical digit lies between 0.1.... to 9.9.....

If the decimal is shifting to right side, the power of 10 is negative and if the decimal is shifting to left side, the power of 10 is positive.

We are given:

A number having value = 0.000000093425

Converting this into scientific notation, we get:

\Rightarrow 0.000000093425=9.342\times 10^{-8}

Hence, the given number in scientific notation is 9.342\times 10^{-8}

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7. How many liters of NH3, at STP will react with 10.6 g O2 to form NO2 and water? 4NH3(g) + 7O2(g) → 4NO2(g) + 6H2O(g) *
Alexus [3.1K]

7) Answer is: c. 4.24 L.

Balanced chemical reaction: 4NH₃(g) + 7O₂(g) → 4NO₂(g) + 6H₂O(g).

m(O₂) = 10.6 g; mass of oxygen.

n(O₂) = m(O₂) ÷ M(O₂).

n(O₂) = 10.6 g ÷ 32 g/mol.

n(O₂) = 0.33 mol; amount of oxygen.

Vm = 22.4 L/mol; molar volume at STP (Standard Temperature and Pressure).

At STP one mole of gas occupies 22.4 liters of volume.

V(O₂) = n(O₂) · Vm.

V(O₂) = 0.33 mol · 22.4 L/mol.

V(O₂) = 7.42 L; volume of oxygen.

From balanced chemical reaction: n(O₂) : n(NH₃) = 7 : 4.

n(NH₃) = 4 · 0.33 mol ÷ 7.

n(NH₃) = 0.188 mol; amount of ammonia.

V(NH₃) = 0.188 mol · 22.4 L/mol.

V(NH₃) = 4.24 L.

8) Answer is: a. 3.7 g.

Balanced chemical reaction: P₄(g) + 6H₂(g) → 4PH₃(g).

m(P₄) = 3.4 g; mass of phosphorous.

n(P₄) = m(P₄) ÷ M(P₄).

n(P₄) = 3.4 g ÷ 123.9 g/mol.

n(P₄) = 0.0274 mol; limiting reactant.

n(H₂) = 4 g ÷ 2 g/mol.

n(H₂) = 2 mol; amount of hydrogen.

From balanced chemical reaction: n(P₄) : n(PH₃) = 1 : 4.

n(PH₃) = 4 · 0.0274 mol.

n(PH₃) = 0.1096 mol.

m(PH₃) = 0.1096 mol · 34 g/mol.

m(PH₃) = 3.726 g.

9) Answer is: d. Percent yield is the ratio of theoretical yield to actual yield expressed as a percent.

Percent yield = actual yield / theoretical yield.

Theoretical yield is the maximum amount of product that can be produced from limiting reactant and actual yield is a product that is obtained by experimentation.

For example:

the percent yield = 250 g ÷ 294.24 g · 100%.

the percent yield = 84.5 %.

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3 years ago
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Answer:

A) Q + XZ = X + QZ is a single displacement reaction.

B) Q + Z = QZ is a synthesis reaction

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D) QT + XZ = QZ + XT is double replacement reaction.

Explanation:

A) Q + XZ = X + QZ

This is a single displacement reaction because it is one in which one element is substituted for another one in a compound. In this case X is substituted for Q.

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C) QT = Q + T

This is a decomposition reaction because the compound QT breaks down to form 2 simpler substances Q and T.

D) QT + XZ = QZ + XT

Thus is a double replacement reaction because QT and XZ have exchanged cations to form new compounds QZ and XT

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