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LenKa [72]
3 years ago
12

What is the periodic trend in atomic size and electronegativity as you move from left to right on the?

Chemistry
1 answer:
Darya [45]3 years ago
6 0
As you move from left to right on the periodic table, atomic size and electronegativity increase.

(Ionization energy increases from left to right on the periodic table, and electronegativity relates to ionization energy in that the higher the ionization energy, the higher the electronegativity.)

(Atomic radius increases from left to right on the periodic table due to the fact that electrons are gradually being added from left to right, meaning the amount of protons in the nucleus are increasing in order to keep the atom neutral, therefore atomic size/radius increases.)
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Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili
Katen [24]

<u>Answer:</u> The value of equilibrium constant for the given reaction is 56.61

<u>Explanation:</u>

We are given:

Initial moles of iodine gas = 0.100 moles

Initial moles of hydrogen gas = 0.100 moles

Volume of container = 1.00 L

Molarity of the solution is calculated by the equation:

\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}

\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M

\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M

Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

                         H_2+I_2\rightleftharpoons 2HI

<u>Initial:</u>                0.1    0.1

<u>At eqllm:</u>          0.1-x   0.1-x   2x

Evaluating the value of 'x'

\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M

The expression of K_c for above equation follows:

K_c=\frac{[HI]^2}{[H_2][I_2]}

[HI]_{eq}=2x=(2\times 0.079)=0.158M

[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M

[I_2]_{eq}=0.0210M

Putting values in above expression, we get:

K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61

Hence, the value of equilibrium constant for the given reaction is 56.61

6 0
3 years ago
Whose work directly resulted in the development of an atomic model that has negative electrons stuck within a sea of positive ma
miskamm [114]

Answer: Thomson

Explanation: It verified J. J. Thomson's work on the atomic structure.

3 0
3 years ago
Read 2 more answers
Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:
Bad White [126]

The electron group arrangement of NO²⁻is trigonal planar. The molecular shape is bent, and the bond angle is 120°.

<h3>What is the molecular shape of a compound?</h3>

The molecular geometry of the compound shows the position of nuclei and the electron of the compound. It shows how the joining of electrons and nuclei makes the shape of the compound.

Like here, the shape of nitrite is bent with lone pair which is shown by Lewis's structure The bond angle will be the distance between the nuclei of the neighbor atoms.

Thus, the electron geometry arrangement of nitrite is trigonal planer with a bent shape and the bond angle will be 120°.

To learn more about molecular geometry, refer to the link:

brainly.com/question/7558603

#SPJ4

5 0
1 year ago
47.0ml of a HBr solution were titrated with 37.5ml of a 0.215M LiOH solution to reach the equivalence point. what is the molarit
faltersainse [42]

Hello!

The molarity of the HBr solution is 0,172 M.

Why?

The neutralization reaction between LiOH and HBr is the following:

HBr(aq) + LiOH(aq) → LiBr(aq) + H₂O(l)

To solve this exercise, we are going to apply the common titration equation:

M1*V1=M2*V2

M1=\frac{M2*V2}{V1}= \frac{0,215 M * 37,5 mL}{47 mL}=0,172 M

Have a nice day!

4 0
3 years ago
How many grams of nh3 can be produced from 2.86 mol of n2 and excess h2?
IRISSAK [1]
I think <span>3H2+N2==>2NH3</span>
7 0
3 years ago
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