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3 years ago

What is the periodic trend in atomic size and electronegativity as you move from left to right on the?

1 answer:

6 0

As you move from left to right on the periodic table, atomic size and electronegativity increase.

(Ionization energy increases from left to right on the periodic table, and electronegativity relates to ionization energy in that the higher the ionization energy, the higher the electronegativity.)

(Atomic radius increases from left to right on the periodic table due to the fact that electrons are gradually being added from left to right, meaning the amount of protons in the nucleus are increasing in order to keep the atom neutral, therefore atomic size/radius increases.)

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A ball of mass 0.2 kg is dropped from a height of 10 m. How much mechanical energy does it have right before it hits the ground?

lana [24]

Answer:

19.6 J

Step-by-step explanation:

Before the ball is dropped, it has a potential energy

PE = mgh

PE = 0.2 × 10 × 9.8

PE = 19.6 J

Just before the ball hits the ground, the potential energy has been converted into kinetic (mechanical) energy.

KE = 19.6 J

3 0

3 years ago

The mechanical advantage required to lift a clay block?

Oxana [17]

Electrical?

Hope this helps

7 0

3 years ago

Read 2 more answers

Which set of these comparisons is incorrect? (more stable means it has a more negative energy.)

Lady bird [3.3K]

I think your anwser ahould be b!

4 0

3 years ago

two kilogram of nasialo4 zeolites are used in a water filter to remove calcium. after complete ion exchange the zeolite is remov

defon

After ion exchange with zeolite in water filter to remove calcium by substitute natrium ion with calcium ion, the weight of zeolite become 1.9578 kg.

ion exchange calculation can be done by using basic stoichiometry if we know how the reaction of the ion exchange. In this case where zeolite with natrium ion will be exchanged with calcium. The reaction of exchange will be like this:

$2NaSiAlO_{4} + Ca^{2+}$ ⇒ $Ca(SiAlO_{4}) _{2} + 2Na^{+}$

Calculate the molecule weight of both zeolite
Atomic weight data:
Na = 23 gram/mole

Si = 28 gram/mole

Al = 27 gram/mole

O = 16 gram/mole

Ca = 40 gram/mole

Molecule weight

$NaSiAlO_{4}$ = 142 gram/mole

$Ca(SiAlO_{4}) _{2}$ = 278 gram/mole

Calculate mole from 2kg of zeolite with natrium :

2000 gram/ 142 = 14.0845 mole

Based on the stoichiometry, we got the mole of zeolite with calcium:

14.0845 mole x 1/2 = 7.0423 mole

Weight of zeolite after the ion exchanged with calcium:

7.0423 mole x 278 = 1957.8 gram = 1.9578 kg

Learn more about ion exchange here: brainly.com/question/28203551

#SPJ4

6 0

1 year ago

She introduced 0.174 moles of nobr(g) into a 1.00 liter container, she found the equilibrium concentration of br2(g) to be 1.79×

Nastasia [14]

The equilibrium reaction is

2 NOBr ⇄ 2 NO + Br₂

The initial molarity of NOBr is 0.174 mol/1 L = 0.174 M. Let's apply the ICE approach which stands for Initial-Change-Equilibrium.

2 NOBr ⇄ 2 NO + Br₂
I 0.174 0 0
C -2x +2x +x
----------------------------------------------------
E 0.174-2x 2x x

Since E for Br₂ is 1.79*10⁻² M, then that means x = 1.79*10⁻² M. We can compute E for the other compounds.

E for NOBr = 0.174 - 2(1.79*10⁻²) = 0.1382 M
E for NO = 2(1.79*10⁻²) = 0.0358 M

The expression for Kc according to the reaction is:
Kc = [NO]²[Br₂]/[NOBr]²
Kc = [0.0358]²[1.79*10⁻²]/[0.1382]²
Kc = 1.2×10⁻³

6 0

3 years ago