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andreyandreev [35.5K]
3 years ago
8

Free use of uniforms and socialization with classmates are possible advantages of ? A.)

Physics
1 answer:
Galina-37 [17]3 years ago
8 0
The answer is B community based sports program
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Red laser light from a He-Ne laser (λ = 632.8 nm) creates a second-order fringe at 53.2° after passing through the grating. What
Svetlanka [38]

Explanation:

It is given that,

Wavelength of red laser light, \lambda=632.8\ nm=632.8\times 10^{-9}\ m

The second order fringe is formed at an angle of, \theta=53.2^{\circ}

For diffraction grating,

d\ sin\theta=n\lambda

d=\dfrac{n\lambda}{sin\theta}, n = 2

d=\dfrac{2\times 632.8\times 10^{-9}}{sin(53.2)}

d=1.58\times 10^{-6}\ m

The wavelength λ of light that creates a first-order fringe at 22 is given by :

\lambda=d\ sin\theta

\lambda=1.58\times 10^{-6}\ sin(22)

\lambda=5.91\times 10^{-7}\ m

\lambda=591\ nm

Hence, this is the required solution.

6 0
3 years ago
A wagon with an initial velocity of 2 m/s and a mass of 60 kg, gets a push with 150 joules of
Aleks04 [339]

Answer:

v_f = 3 m/s

Explanation:

From work energy theorem;

W = K_f - K_i

Where;

K_f is final kinetic energy

K_i is initial kinetic energy

W is work done

K_f = ½mv_f²

K_i = ½mv_i²

Where v_f and v_i are final and initial velocities respectively

Thus;

W = ½mv_f² - ½mv_i²

We are given;

W = 150 J

m = 60 kg

v_i = 2 m/s

Thus;

150 = ½×60(v_f² - 2²)

150 = 30(v_f² - 4)

(v_f² - 4) = 150/30

(v_f² - 4) = 5

v_f² = 5 + 4

v_f² = 9

v_f = √9

v_f = 3 m/s

7 0
2 years ago
He electron cloud is the predicted location for
DanielleElmas [232]

Answer:

A) Electrons only

Explanation:

In quantum mechanics, "electron cloud" refers to the region of space where electrons can be found in an atom. In fact, in quantum mechanics, it is not possible to predict the exact position of the electrons, so there is a region where electrons have a certain probability to be found.

7 0
3 years ago
Help plz. Even when you're not moving, your body needs energy for functions such as breathing, circulating blood and repairing c
KatRina [158]

<u>ANSWER</u>

metabolism

I really hope this helps i am in middle school and this must be a high school question.

4 0
3 years ago
11. एक समान चुम्बकीय क्षेत्र में लम्बवत प्रवेश करने वाले किसी आवेशित कण द्वारा प्राप्त वृत्तीय पथ की
mojhsa [17]

Answer:

<h2> r=mv/Be</h2>

Explanation:

If a positive charge enters a magnetic field at 90 degrees the charge is deflected in a circular path by a force that acts perpendicular to it in line with Flemings right-hand rule

to derive the radius of the path of the charge we apply

F= mv^2/r=Bev

where

m= mass of the electronic charge

e=charge

B=magnetic field

v=average speed

r=radius

 

rearranging we have

r=mv^2/Bev

r=mv/Be

5 0
3 years ago
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