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velikii [3]
2 years ago
13

It is more difficult to start moving a heavy carton from rest than it is to keep pushing it with a constant velocity because

Physics
2 answers:
insens350 [35]2 years ago
6 0
Kinetic friction is less than static friction.
mel-nik [20]2 years ago
3 0

Answer:

This is because the heavy carton requires a net force to move.

Explanation:

When the carton is initially at rest, its acceleration is zero. A force F which is greater than the static frictional force, f on it has to be exerted on it to produce a net force which will thus produce a net acceleration.

So, F - f = ma. So, F = f + ma.

So, the force applied, equals the net force plus the frictional force on the heavy carton.

At constant velocity, the acceleration is zero and thus the net force required to keep the object in motion just balances the kinetic friction on it. If F is the force applied and f the kinetic friction, F - f = ma = 0. So, F = f which is less than calculated above.

So, a heavy carton is more difficult to move from rest than to keep pushing it with a constant velocity because, a net force is required to start moving the heavy carton from rest,and no net force is required to keep pushing it at constant velocity.

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Answer:

D= Seven

Explanation:

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2 years ago
A basketball is shot from 2 meters up at an angle of 60° above the x axis at an initial velocity of 9 m/s. What is the maximum h
Nikitich [7]

Hope this helps a little

initial distance up = 2

initial velocity component up = 9 sin 60 = 7.79

v = 9 sin 60 - 9.8 t

when v = 0, we are there

9.8 t = 7.79

t = .795 seconds to top

h = 2 + 7.79(.795) - 4.9(.795^2)

7 0
3 years ago
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Electronegativity increases when atoms ___
notka56 [123]

your answer is.....

D. have a large atomic radius

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8 0
3 years ago
A satellite that goes around the earth once every 24 hours (86,400 s) is called a geosynchronous satellite. If a geosynchronous
Olegator [25]

Answer:

42244138.951 m

Explanation:

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r = Radius of orbit from center of earth

M = Mass of Earth = 5.98 × 10²⁴ kg

m = Mass of Satellite

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Speed = Distance / Time

The distance is the perimeter of the orbit

v=\frac{2\pi \times r}{24\times 3600}

The Centripetal force of the satellite is balanced by the universal gravitational force

m\frac{v^2}{r}=\frac{GMm}{r^2}\\\Rightarrow \frac{\left(\frac{2\pi \times r}{24\times 3600}\right)^2}{r}=\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}}{r^2}\\\Rightarrow \left(\frac{2\pi \times r}{24\times 3600}\right)^2=6.667\times 10^{-11}\times 5.98\times 10^{24}\\\Rightarrow r^3=\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}\times (24\times 3600)^2}{(2\pi)^2}\\\Rightarrow r=\left(\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}\times (24\times 3600)^2}{(2\pi)^2}\right)^{\frac{1}{3}}\\\Rightarrow r=42244138.951\ m

The radius as measured from the center of the Earth) of the orbit of a geosynchronous satellite that circles the earth is 42244138.951 m

6 0
3 years ago
Which is an example of action and reaction forces?
Vlad [161]

Hey there!

the answer is

C. a tennis racket striking a tennis ball

Thank you

Best regards

           OFFICIALLYSAVAGE2003

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3 years ago
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