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3 years ago

It is more difficult to start moving a heavy carton from rest than it is to keep pushing it with a constant velocity because

Physics

2 answers:

insens350 [35]3 years ago

6 0

Kinetic friction is less than static friction.

mel-nik [20]3 years ago

3 0

Answer:

This is because the heavy carton requires a net force to move.

Explanation:

When the carton is initially at rest, its acceleration is zero. A force F which is greater than the static frictional force, f on it has to be exerted on it to produce a net force which will thus produce a net acceleration.

So, F - f = ma. So, F = f + ma.

So, the force applied, equals the net force plus the frictional force on the heavy carton.

At constant velocity, the acceleration is zero and thus the net force required to keep the object in motion just balances the kinetic friction on it. If F is the force applied and f the kinetic friction, F - f = ma = 0. So, F = f which is less than calculated above.

So, a heavy carton is more difficult to move from rest than to keep pushing it with a constant velocity because, a net force is required to start moving the heavy carton from rest,and no net force is required to keep pushing it at constant velocity.

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A baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of 4kg. The carriage ha

Ira Lisetskai [31]

Answer:

E=252J

Explanation:

The total mechanical energy of an object or system is given by:

E mech=K+U

Where K is the kinetic energy of the object and U is the potential energy of the object. The carriage, sitting motionless at the top of the hill, has only potential energy in the form of gravitational potential energy.

Gravitational potential energy is given by:

Ug=mgh

Where m is the mass of the object, g is the gravitational acceleration constant, and h is the height of the object above some specific reference point, in this case the ground 21 m below.

The weight of a stationary object at the surface of the earth is equal to the force of gravity acting on the object.

W=→Fg=mg

We are given that the carriage weighs 12 N, therefore mg=12N.

Ug=12N⋅21m

⇒Ug=252Nm=252J

Hope it helped, God bless you!

5 0

3 years ago

Car A is traveling west at 40 mi/h and car B is traveling north at 40 mi/h. Both are headed for the intersection of the two road

Gwar [14]

Explanation:

It is given that,

$\frac{dx}{dt}$ = -40 mi/h, $\frac{dx}{dt}$ = -40 mi/h

The negative sign indicates that x and y are decreasing.

We have to find $\frac{dz}{dt}$ . Equation for the given variables according to the Pythagoras theorem is as follows.

$z^{2} = x^{2} + y^{2}$

Now, we will differentiate each side w.r.t 't' as follows.

$2z\frac{dz}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}$

or, $\frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})$

So, when x = 4 mi, and y = 3 mi then z = 5 mi.

As, $\frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})$

= $\frac{1}{5}(4 \times (-40) + 3 \times (-40))$

= $\frac{-140 - 120}{5}$

= 52

Thus, we can conclude that the cars are approaching at a rate of 52 mi/h.

7 0

3 years ago

Which of the 3 states of matter is easier to increase the temperature by one degree; in a liquid, in a solid, or in a gas?

Mashcka [7]

Answer:

gas

Explanation:

this is bcz they have higher kinetic energy compared to liquids and gases

4 0

3 years ago

As you sit in a chair, in what direction (or directions) do you exert an action force?

enyata [817]

As we sit in a chair, Action force will be only in one direction and that direction would be downward only.

In short, Your Answer would be Option A

Hope this helps!

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3 years ago

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weeeeeb [17]

C. It transfer energy as heat to the surrounding air. This answer is incorrectly

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2 years ago