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velikii [3]
3 years ago
13

It is more difficult to start moving a heavy carton from rest than it is to keep pushing it with a constant velocity because

Physics
2 answers:
insens350 [35]3 years ago
6 0
Kinetic friction is less than static friction.
mel-nik [20]3 years ago
3 0

Answer:

This is because the heavy carton requires a net force to move.

Explanation:

When the carton is initially at rest, its acceleration is zero. A force F which is greater than the static frictional force, f on it has to be exerted on it to produce a net force which will thus produce a net acceleration.

So, F - f = ma. So, F = f + ma.

So, the force applied, equals the net force plus the frictional force on the heavy carton.

At constant velocity, the acceleration is zero and thus the net force required to keep the object in motion just balances the kinetic friction on it. If F is the force applied and f the kinetic friction, F - f = ma = 0. So, F = f which is less than calculated above.

So, a heavy carton is more difficult to move from rest than to keep pushing it with a constant velocity because, a net force is required to start moving the heavy carton from rest,and no net force is required to keep pushing it at constant velocity.

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Assume a change at the source of sound reduces the wavelength of a sound wave in air by a factor of 3.
noname [10]

Explanation:

The speed of a wave is given by :

v=f\lambda ......(1)

(i) Here, the wavelength of a sound wave in air reduces by a factor of 3. Equation (1) becomes :

\lambda=\dfrac{v}{f}

Wavelength and frequency are inversely proportional to each other. So, if wavelength of a sound wave in air reduces by a factor of 3, then the frequency will increases by a factor of 3.

(ii) It remains the same.

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3 years ago
Two cars cover the same distance in a straight line. Car A covers the distance at a constant velocity. Car B starts from rest an
SpyIntel [72]

Answer:

a) 2.43 m/s

b) 4.83 m/s

c) 0.023 m/s²

Explanation:

a) Both cars cover a distance of 510 m in 210 s. Since car A has no acceleration

Speed = Distance / Time

\text{Speed}=\frac{510}{210}=2.43\ m/s

Velocity of car A is 2.43 m/s

t = Time taken = 210 seconds

u = Initial velocity

v = Final velocity

s = Displacement = 510 m

a = Acceleration

c)

s=ut+\frac{1}{2}at^2\\\Rightarrow 510=0\times 210+\frac{1}{2}\times a\times 210^2\\\Rightarrow a=\frac{510\times 2}{210^2}\\\Rightarrow a=0.023\ m/s^2

Acceleration of car B is 0.023 m/s²

b)

v=u+at\\\Rightarrow v=0+0.023\times 210\\\Rightarrow v=4.83\ m/s

Final velocity of car B is 4.83 m/s

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3 years ago
The metric unit of force is the
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Newtons. Force is mass times acceleration. Mass is measured in kilograms (kg) and acceleration is measured in meters per second squared (m/s^2.) These units (kg and m/s^2) multiplied together like in the equation force equals mass times acceleration (F=ma) gives a product with Newtons as the unit. 
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Para que sirve la caida libre
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