Answer:
<em>a. The cart's acceleration is 2 m/s^2</em>
<em>b. The cart will travel 100 m</em>
<em>c. The speed is 20 m/s</em>
Explanation:
a. The acceleration of the cart can be calculated using Newton's second law:
F = m.a
Solving for a:

The cart has a mass of m=15 Kg and is applied a net force of F=30 N, thus:


b.
Now we use kinematics to find the distance and speed:

The cart starts from rest (vo=0). The distance traveled in t=10 seconds is:


The cart will travel 100 m
c.
The final speed is calculated by:

The speed is 20 m/s
Hi!
Neutrons are neutral, which means they don't exactly have an electrical charge. It's because of this neutral charge that it is represented with a '0'.
On the other hand, protons and electrons <em>do </em>have electrical charges. Electrons flow around the outside of the nucleus, with a negative charge.
Protons are stored in the nucleus with the neutrons, holding a positive charge.
Hopefully, this helps! =)
Answer: The verb phrase can be found in the last sentence(?
The frequency of the wave is 132 Hz
Explanation:
To calculate the speed of the wave, we can use the following formula:

where
d is the distance travelled by the wave
t is the time elapsed
For the sound wave in this problem, we have:
d = 660 m is the distance travelled
t = 2 s is the time interval considered
Substituting and solving for v, we find the speed of the sound wave:

Now we can calculate the frequency of the wave by using the wave equation:

where
v = 330 m/s is the speed of the wave
is the wavelength
f is the frequency
Solving for f, we find:

Learn more about wavelength and frequency:
brainly.com/question/5354733
brainly.com/question/9077368
#LearnwithBrainly
Answer:
The total resistance of the wire is = 
Explanation:
Since the wires will both be in contact with the voltage source at the same time and the current flows along in their length-wise direction, the two wires will be considered to be in parallel.
Hence, for resistances in parallel, the total resistance, 

Parameters given:
Length of wire = 1 m
Cross sectional area of copper 
Cross sectional area of aluminium wire
![A_{al}= \pi( R^{2}-r^{2})\\\\ = \pi \times [ (2\times 10^{-3} )^{2}-(1\times 10^{-3} )^{2}] =9.42\times10^{-6} m^{2}\\](https://tex.z-dn.net/?f=A_%7Bal%7D%3D%20%5Cpi%28%20R%5E%7B2%7D-r%5E%7B2%7D%29%5C%5C%5C%5C%20%3D%20%5Cpi%20%5Ctimes%20%5B%20%282%5Ctimes%2010%5E%7B-3%7D%20%20%29%5E%7B2%7D-%281%5Ctimes%2010%5E%7B-3%7D%20%20%29%5E%7B2%7D%5D%20%3D9.42%5Ctimes10%5E%7B-6%7D%20m%5E%7B2%7D%5C%5C)
Resistivity of copper 
Resistivity of Aluminium 
Resistance of copper 
Resistance of aluminium 
The total resistance of the wire can be obtained as follows;


∴ The total resistance of the wire = 