6x^3 + 5y^3 + 7y
So the third option.
Given two sets X and Y, a relation between X and Y freely associates elements of X with elements of Y, with no restrictions.
A function is a relation with some restrictions: there must be exactly one element of Y connected with each element of X.
The set X is called the domain of the function, and it represents all the possible inputs that we can feed the function with. As we just said, every element of the domain must have a correlated element in Y.
The set Y is called the range of the function, and it represents all the possible outputs that the function can return.
Answer:
=344
Step-by-step explanation:
(43)(8)
=344
Answer:
Step-by-step explanation:
f(x)= - 3x
g(x) = x+2
(f•g)(x)
f(x) • g(x)
plug in
-3x • x+2
-3x(x+2)
distribute the -3x
hope this helps!
Answer:
(a) true
(b) true
(c) false; {y = x, t < 1; y = 2x, t ≥ 1}
(d) false; y = 200x for .005 < |x| < 1
Step-by-step explanation:
(a) "s(t) is periodic with period T" means s(t) = s(t+nT) for any integer n. Since values of n may be of the form n = 2m for any integer m, then this also means ...
s(t) = s(t +2mt) = s(t +m(2T)) . . . for any integer m
This equation matches the form of a function periodic with period 2T.
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(b) A system being linear means the output for the sum of two inputs is the sum of the outputs from the separate inputs:
s(a) +s(b) = s(a+b) . . . . definition of linear function
Then if a=b, you have
2s(a) = s(2a)
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(c) The output from a time-shifted input will only be the time-shifted output of the unshifted input if the system is time-invariant. The problem conditions here don't require that. A system can be "linear continuous time" and still be time-varying.
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(d) A restriction on an input magnitude does not mean the same restriction applies to the output magnitude. The system may have gain, for example.
