This can be solve using the formula P = I^2 * Rwhere P is the powerI is the CurrentR is the resistanceP = I^2 * R
1/4 Watt = I^2 * 100 ohm solve for II^2 = 1/400 I = 0.05 amps then using the formula to solve for the voltage:V = I * RV = 0.05 amps * 100 ohms V = 5 volts
Answer:
With the addition of the pipe we have a greater torque.
Explanation:
We need to complete the description of the problem, searchin in internet we have:
"Sometimes, even with a wrench, one cannot loosen a nut that is frozen tightly to a bolt. It is often possible to loosen the nut by slipping one end of a long pipe over the wrench handle and pushing at the other end of the pipe. With the aid of the pipe, does the applied force produce a smaller torque, a greater torque, or the same torque on the nut?"
With the addition of the pipe we have a greater torque, as it increases the distance or radius of torque.
We know that torque is defined, as the product of force by distance, in this way we have:
T = F * d
where:
T = torque [N*m]
F = force [N]
d = distance [m]
We can see in the above equation, that increasing the distance increases torque proportionally.
Answer:
Explanation:
I = Moment of inertia = 
m = Mass of two atoms = 2m = 
r = distance between axis and rotation mass
Moment of inertia of the system is given by
The distance between the atoms will be two times the distance between axis and rotation mass.
Therefore, the distance between the two atoms is
Answer:
variables on the horizontal and vertical axis (slope, outliers, +/- correlation, etc)
Explanation:
