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3 years ago

Why is it so important to know how the parts of a can opener work

Physics

1 answer:

Dafna1 [17]3 years ago

3 0

Answer:

Hi there!

There are many possible answers!

My best guesses are:

1) Knowing how they work will prevent injury! For example, knowing that the gears twist will stop you from putting your finger in it!

2) Allowing you to use it! Knowing how to line up the edge of the can with the tool will let you use it properly!

Hope this helps

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For this triangle...?

Mariulka [41]

<h3><u>Answer</u>;</h3>

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<h3><u>Explanation</u>;</h3>

Using Pythagoras theorrem

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Thus;

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= 81

Base = √81 = 9

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3 years ago

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3 years ago

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3 years ago

(25 pts) Estimate how much collector area and storage capacity would be required for an active solar hot-water system designed t

Aneli [31]

Answer:

The required total area is 1.48 m²

Explanation:

Given that,

Latitude = 44+° N

New Mexico,

Latitude= 35+° N

Heat capacity = 4200 J/Kg°C

Temperature = 60°C

Let us assume the input temperature 22°C

Estimate volume of water 100 ltr for 4 person.

We need to calculate the heat

Using formula of heat

$H=mc_{p}\Delta T$

$H=mc_{p}(T_{f}-T_{i})$

Put the value into the formula

$H=100\times4200\times(60-22)$

$H=15960\ KJ$ ...(I)

Let solar radiation for 6 hours/day.

We need to calculate the total energy per unit area

Using formula of energy

$E=1000\times6\times3600\ J/m^2$

$E=21600\ KJ/m^2$

Let the efficiency of collector is 50 %

Then, the total energy per unit area will be

$E=21600\times\dfrac{50}{100}$

$E=10800\ KJ/m^2$ ....(II)

We need to calculate the required total area

Using equation (I) and (II)

$A=\dfrac{H}{E}$

Where, H = heat

E = total energy

Put the value into the formula

$A=\dfrac{15960}{10800}$

$A=1.48\ m^2$

Hence, The required total area is 1.48 m²

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3 years ago