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vovangra [49]
3 years ago
5

The unit cm2 is used to measure: mass area volume length

Physics
1 answer:
Thepotemich [5.8K]3 years ago
4 0

Answer:

cm^2 is used to measure (surface) area .

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Calculate the speed of a proton after it accelerates from rest through a potential difference of 350 V.
AVprozaik [17]

The speed of a proton after it accelerates from rest through a potential difference of 350 V is 25.86 \times 10^4 ~m/s.

Initial velocity of the proton u = 0

Given potential difference \Delta V = 350V

let's assume that the speed of the proton is v,

Since the proton is accelerating through a potential difference, proton's potential energy will change with time. The potential energy of a particle of charge q when accelerated with a potential difference \Delta V is,

    U = q \Delta V

Due to Work-Energy Theorem and Conservation of Energy - <em>If there is no non-conservative force acting on a particle then loss in Potential energy  P.E must be equal to gain in Kinetic Energy K.E</em> i.e

\Delta K = \Delta V

If the initial and final velocity of the proton is u and v respectively then,

change in Kinetic Energy  \implies  \Delta K = \frac{1}{2}mv^2 -\frac{1}{2}mu^2 = \frac{1}{2}mv^2 - 0

change in Potential Energy \implies \Delta U = q\Delta V

from conservation of energy,

             v= \sqrt{\frac{2q\Delta V}{m}}

so,         v = \sqrt{\frac{2\times 350 \times 1.6\times 10^{-19}}{1.67 \times 10^{-27}}

                = 25.86 \times 10^4 ~m/s

To read more about the conservation of energy, please go to brainly.com/question/14668053

7 0
1 year ago
Two identical trucks have mass 5100 kg when empty, and the maximum permissible load for each is 8000 kg. the first truck, carryi
Oksanka [162]
<span>The 2nd truck was overloaded with a load of 16833 kg instead of the permissible load of 8000 kg. The key here is the conservation of momentum. For the first truck, the momentum is 0(5100 + 4300) The second truck has a starting momentum of 60(5100 + x) And finally, after the collision, the momentum of the whole system is 42(5100 + 4300 + 5100 + x) So let's set the equations for before and after the collision equal to each other. 0(5100 + 4300) + 60(5100 + x) = 42(5100 + 4300 + 5100 + x) And solve for x, first by adding the constant terms 0(5100 + 4300) + 60(5100 + x) = 42(14500 + x) Getting rid of the zero term 60(5100 + x) = 42(14500 + x) Distribute the 60 and the 42. 60*5100 + 60x = 42*14500 + 42x 306000 + 60x = 609000 + 42x Subtract 42x from both sides 306000 + 18x = 609000 Subtract 306000 from both sides 18x = 303000 And divide both sides by 18 x = 16833.33 So we have the 2nd truck with a load of 16833.33 kg, which is well over it's maximum permissible load of 8000 kg. Let's verify the results by plugging that mass into the before and after collision momentums. 60(5100 + 16833.33) = 60(21933.33) = 1316000 42(5100 + 4300 + 5100 + 16833.33) = 42(31333.33) = 1316000 They match. The 2nd truck was definitely over loaded.</span>
6 0
3 years ago
The trade winds are tropical winds that blow toward the Equator. Choose the statement that best explains why the trade winds blo
AveGali [126]

The best and most correct answer among the choices provided by your question is the fourth option or letter D. Trade winds blow towards the equator because t<span>he Equator receives the most heat energy.

</span>The surface air that flows from these subtropical high-pressure belts toward the Equator is deflected toward the west in both hemispheres by the Coriolis effect. These winds blow<span> predominantly from the northeast in the Northern Hemisphere and from the southeast in the Southern Hemisphere.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

</span>

3 0
3 years ago
Consider each of the electric- and magnetic-field orientations given next. In each case, what is the direction of propagation of
vodka [1.7K]

The route of the propagation of the wave in every case are; A) +z route B) +z route C) -y route D) -x route .

vec Ein is the Electrical area vector and vec Bin is the Magnetic area vector, due to the fact the sphere vectors are continually perpendicular to every different the propagation of the wave is perpendicular to the 2 vectors. The route of the propagation of the wave may be observed with the aid of using vec Ein X vec Bin (Cross made from vectors). This also can be achieved with the aid of using the usage of the RIGHT HAND RULE.

Cross product may be observed with the aid of using

i x j = okay and j x i = - okay

j x okay=i and okay x j = - i

okay x i=j and that i x okay = - j

wherein i represents the +x route, j represents the +y route and okay represents the +z route

The RIGHT HAND RULE may be used to demonstrate the move product with the aid of using the usage of the proper hand and pointing the index finger withinside the route of the primary vector and the center finger alongside the second one vector, the move product is withinside the route of the thumb.

A) vec Ein the +xdirection,vec Bin the +ydirection,

Finding the move made from the 2 vectors (i x j = okay) might provide a vector withinside the +z route

B) vec Ein the -y route,vec Bin the +x route

Finding the move made from the 2 vectors (- j x i = okay) might provide a vector withinside the +z route

C) vec Ein the +z route,vec Bin the -x route

Finding the move made from the 2 vectors (okay x - i = - j) might provide a vector withinside the -y route

D) vec Ein the +y route,vec Bin the -z route

Finding the move made from the 2 vectors (j x - okay = - i) might provide a vector withinside the -x route

The complete question is- Consider each of the electric- and magnetic-field orientations given next. In each case, what is the direction of propagation of the wave?A)\vec Ein the +xdirection,\vec Bin the +ydirection.Please Choose+ x direction- x direction+ y direction- y direction+ z direction- z directionB)\vec Ein the -y direction,\vec Bin the +x directionPlease Choose+ x direction- x direction+ y direction- y direction+ z direction- z directionC)\vec Ein the +z direction,\vec Bin the -x direction.Please Choose+ x direction- x direction+ y direction- y direction+ z direction- z directionD)\vec Ein the +y direction,\vec Bin the -z direction.Please Choose+ x direction- x direction+ y direction- y direction+ z direction- z direction.

Learn more about vector here-

brainly.com/question/13966790

#SPJ4

3 0
10 months ago
A) 1.2-kg ball is hanging from the end of a rope. The rope hangs at an angle 20° from the vertical when a 19 m/s horizontal wind
Marat540 [252]

Answer:

Part a)

F_v = 4.28 N

Part B)

L = 1.02 m

Part C)

v = 1.25 m/s

Explanation:

Part A)

As we know that ball is hanging from the top and its angle with the vertical is 20 degree

so we will have

Tcos\theta = mg

T sin\theta = F_v

\frac{F_v}{mg} = tan\theta

F_v = mg tan\theta

F_v = 1.2\times 9.81 (tan20)

F_v = 4.28 N

Part B)

Here we can use energy theorem to find the distance that it will move

-\mu mg cos\theta L + mg sin\theta L = -\frac{1}{2}mv^2

(-(0.37)m(9.81) cos15 + m(9.81) sin15)L = - \frac{1}{2}m(1.4)^2

(-3.5 + 2.54)L = - 0.98

L = 1.02 m

Part C)

At terminal speed condition we know that

F_v = mg

bv^2 = mg

2.5 v^2 = 3.9

v = 1.25 m/s

7 0
3 years ago
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