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makvit [3.9K]
2 years ago
10

Which triangle is a 30°-60°-90° triangle?

Mathematics
1 answer:
Arturiano [62]2 years ago
5 0

Answer:

option one is right

Step-by-step explanation:

the very first triangle is the 30 -69 -90 degree triangle ️

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Roberto will roll a number cube and flip a coin. The faces of the number cube are labeled 1 through 6. The coin can land on head
Lyrx [107]

Answer: There are 3 even numbers on the cube. There are 2 sides to a coin. there is a 1/2 chance of the cube landing on an even number. There is a 1/2 chance of the coin landing on tails.

There is a 1/4 chance of these events occurring together.

6 0
2 years ago
Do both of them for 50 points
erastovalidia [21]

Answer:

1) 5.44, 2) 3.9

Step-by-step explanation:

1) a/b + 2b - a^2 when a = 1.4 and b = 0.2

plug in the values:

1.4/0.2 + 2(0.2) - (1.4)^2 = 7 + 0.4 - 1.96 = 5.44

2) a[b-2c]^3 - d/e when a = 2, b = -0.75, c = -1, d = 0, e = -12 5/7 (rewritten to -89/7 = 12.71)

again, plug in the values:

2[-0.75-2(-1)]^3 - 0/12.71 = 2[1.25]^3 - 0 = 2[1.95] = 3.9

5 0
2 years ago
A rectangular pyramid has a height of 8 meters. The base is 7 meters in length and 15 meters in width two different triangular c
vagabundo [1.1K]

Answer:

The difference in the areas of the cross section is 32 m²

Step-by-step explanation:

The given parameters are;

The height of the rectangular pyramid = 8 meters

The length of the base of the pyramid = 7 meters

The width of the base of the pyramid = 15 meters

Whereby triangular cross sections are formed through the vertex and perpendicular to the base, and to each other, we have;

The sides of the two triangles consists of the following;

1) Two slant height of the pyramid each

2) The two perpendicular lines joining the midpoints of the opposite sides of the base of the pyramid with length equal to the length of the adjacent side to the sides from which they are drawn which are 15 meters and 7 meters

3) The two lines and the corresponding slant height form triangles cross section which are perpendicular to each other.

the slant height, h_l, is given as follows;

h_l = √(8² + (15/2)²) ≈ 10.966

For the triangular cross section with base = 15 m

The area of the cross section = 1/2 × Base₁₅ × Height = 1/2 × 15 m × 8 m = 60 m²

For the triangular cross section with base = 7 m

The area of the cross section = 1/2 × Base₇ × Height = 1/2 × 7 m × 8 m = 28 m²

The difference in the areas of the cross section = 60 m² - 28 m² = 32 m².

5 0
3 years ago
Triangle a' B' c' is dilation of triangle abc about point p. Is this a reduction or enlargement<br>​
Yuliya22 [10]

Enlargement

Hope this helps :)

8 0
3 years ago
Hi please please help me
Kaylis [27]

Answer:

141.12 cm^2

Step-by-step explanation:

   Since the area of a trapezoid is the average of the bases multiplied by the height, we can just plug these numbers into the equation! Since the average of 10.2 and 12.2 is 11.2, and the height is 12.6, we multiply them to get the area to be 141.12 cm^2.

6 0
3 years ago
Read 2 more answers
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