The equation that fits the standard form of a Quadratic equation is 2(x + 5)² + 8x + 5 + 6 = 0 which can be re-written as 2x² + 28x + 61 = 0.
<h3>What is a Quadratic Equation?</h3>
Quadratic equation is simply an algebraic expression of the second degree in x. Quadratic equation in its standard form is;
ax² + bx + c = 0
Where x is the unknown
From the given data, we check which of them fits the standard form of a quadratic equation.
- 2(x + 5)² + 8x + 5+ 6 = 0
2(x + 5)² + 8x + 5 + 6 = 0
2( (x(x+5) + 5(x+5) ) + 8x + 5 + 6 = 0
2( x² + 5x + 5x + 25 ) + 8x + 5 + 6 = 0
2( x² + 10x + 25 ) + 8x + 5 + 6 = 0
2x² + 20x + 50 + 8x + 5 + 6 = 0
2x² + 20x + 8x + 50 + 5 + 6 = 0
2x² + 28x + 61 = 0
Therefore, the equation that fits the standard form of a Quadratic equation is 2(x + 5)² + 8x + 5 + 6 = 0 which can be re-written as 2x² + 28x + 61 = 0.
Learn more about quadratic equations here: brainly.com/question/1863222
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Answer:
What is the question
Step-by-step explanation:
Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
