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kkurt [141]
3 years ago
15

Why doesn’t the reaction: Br2(aq) + 2NaCl(aq) → Cl2(aq) + 2NaBr(aq) occur? In other words, why don’t the two Br atoms stop shari

ng an e pair with each other to exist as Br2 and each take an e from the available two Cl ions instead? Answer with respect to the relative E.A. values for Cl and Br. /2
Chemistry
1 answer:
Arte-miy333 [17]3 years ago
6 0

Answer:

Chlorine has higher Electron Affinity as compared to Bromine

Explanation:

Electron affinity is defined as the Potential energy change of the atom when an electron is added to a neutral gaseous atom. Therefore, more the Negative electron affinity, more favorable will be the electron addition process.

The electron affinity of Chlorine is -349kJmol^-1

The electron affinity of Bromine is -324.6KJmol^-1

This clearly shows that Chlorine is a much better Atom to be bonded with, That is the reason why in the reaction is not feasible.

Br2(aq) + 2NaCl(aq) →Cl2(aq) + 2NaBr(aq)

Therefore, Chlorine has higher electron Affinity as compared to Bromine and that what makes it a much better atom to be bonded with Na. So the above reaction is not possible.

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It is the way of cleaning of impurities present in metals

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the volume of a substance must be measured several time during an experiment. which units should be used to measure the volume o
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Answer:

Volume is often measured numerically using the International System of Units (SI unit), the cubic meter. for example volume of a cube is measured using a cubic centimeter (cm3), the metric system includes the liter (L) as a unit of volume, where one liter is the volume of a 10-centimeter cube.

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3 years ago
The charge of the stable ion of S and Li?
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sulfur will have a chafge of -2 and Lithium will have a charge of +1

3 0
4 years ago
Explain the difference in the boiling point of 2-methylpropane and 2-iodo-2-methylpropane in terms of both molecular polarity an
Len [333]
The Boiling Point of 2-methylpropane is approximately -11.7 °C, while, Boiling Point of <span>2-iodo-2-methylpropane is approximately 100 </span>°C.

As both compounds are Non-polar in nature, So there will be no dipole-dipole interactions between the molecules of said compounds.

The Interactions found in these compounds are London Dispersion Forces.

And among several factors at which London Dispersion Forces depends, one is the size of molecule.

Size of Molecule:
                          There is direct relation between size of molecule and London Dispersion forces. So, 2-iodo-2-methylpropane containing large atom (i.e. Iodine) experience greater interactions. So, due to greater interactions 2-iodo-2-methylpropane need more energy to separate from its partner molecules, Hence, high temperature is required to boil them.
6 0
4 years ago
2Li + H2SO4=Li2SO4 + H2 How many liters of hydrogen gas, H2 at STP can be produced from 3.0 moles of Li? The molar volume of a g
Gemiola [76]

Answer:

volume of H_2=33.6 litre

Explanation:

Firstly balance the given chemical equation,

2Li + H_2SO_4=Li_2SO_4 + H_2

From the given balance equation it is clearly that,

2 mole of Li gives  1 mole of H2 gas

2 mole Li⇔1 mole H_2

1 mole Li⇔0.5 mole H_2

3 mole Li⇔1.5 mole H_2

hence

3 mole of Li will give 1.5 mole H2 gas

therefore volume of gas produced from 3 mole Li at STP = 1.5\times22.4 \frac{L}{mol}

volume of H2=33.6 litre

7 0
3 years ago
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