C3H8 -----> 3 CO2 (from equation)
1mol C3H8 ------ 3 mol CO2
2.0 mol C3H8 ---- x mol CO2
x=(2.0 mol C3H8* 3 mol CO2)/1mol C3H8 =6 mol CO2
Answer:
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Explanation:
it occupied more than 8 valence electrons
Answer:
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A) 0.875 M of MgBr2 is 0.875 mol/L
B) 23.7 mL = 0.0237 L
0.875 mol => 1 L
x mol => 0.0237 L
Cross multiply
1x = 0.875 × 0.0237
x = 0.0207 mol
>> In 23.7 mL of 0.875 M MgBr2 solution there is 0.0207 moles of MgBr2
C) Molar mass of MgBr2 (*) = 24.305 + (2 × 79.904) = 184.113 g/mol
184.113 g => 1 mol
x g => 0.0207 mol
Cross multiply
1x = 184.113 × 0.0207
x = 3.8111 g
>> 0.0207 moles of MgBr2 is equivalent to 3.81 g of MgBr2
>> In 23.7 mL of 0.875 M MgBr2 solution there is 3.81 g of MgBr2
(*) Use your periodic table