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3 years ago

Calculate the speed of a wave with a wavelength of 6 meters and a frequency of 3 hertz.

Chemistry

2 answers:

kupik [55]3 years ago

4 0

Painted 18 because the wave length is 6 m and the frequency is 3.So 6×3 = 18

Kruka [31]3 years ago

3 0

The answer is 18 you multiply wavelength (6) times frequency (3)

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Chemists perform experiments to find out how different kinds of matter can change and ______.

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3 years ago

This is how osmium appears in the periodic table. Rounded to the nearest whole number, how many neutrons, on average, are in an

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4 years ago

Read 2 more answers

The liquid inside the cell is called

rodikova [14]

Answer:

The cytoplasm

Explanation:

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5 0

3 years ago

What mass of Hg will occupy a volume of 75.0 mL?

k0ka [10]

75.0 mL in liters:

75.0 / 1000 => 0.075 L

1 mole -------------------- 22.4 L ( at STP)
( moles Hg) ------------- 0.075 L

moles Hg = 0.075 x 1 / 22.4

moles = 0.075 / 22.4

= 0.00334 moles of Hg

Hg => 200.59 u

1 mole Hg ----------------- 200.59 g
<span>0.00334 moles Hg ----- ( mass Hg )
</span>
mass Hg = 200.59 x 0.00334 / 1

mass Hg = 0.6699 / 1

= 0.6699 g of Hg

7 0

3 years ago

What is the limiting reactant and theoretical yield if 0.483 mol of Ti and 0.911 mol Clare used in this reaction: Ti + 2Cl2 → Ti

Mariana [72]

Answer : The limiting reactant is $Cl_2$ and the theoretical yield will be 86.45 grams.

Explanation : Given,

Moles of $Ti$ = 0.483 mole

Moles of $Cl_2$ = 0.911 mole

Molar mass of $TiCl_4$ = 190 g/mole

First we have to calculate the limiting and excess reagent.

The given balanced chemical reaction is,

$Ti+2Cl_2\rightarrow TiCl_4$

From the balanced reaction we conclude that

As, 2 moles of $Cl_2$ react with 1 mole of $Ti$

So, 0.911 moles of $Cl_2$ react with $\frac{0.911}{2}=0.455$ moles of $Ti$

From this we conclude that, $Ti$ is an excess reagent because the given moles are greater than the required moles and $Cl_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $TiCl_4$ .

As, 2 moles of $Cl_2$ react to give 1 moles of $TiCl_4$

So, 0.911 moles of $Cl_2$ react to give $\frac{0.911}{2}=0.455$ moles of $TiCl_4$

Now we have to calculate the mass of $TiCl_4$ .

$\text{Mass of }TiCl_4=\text{Moles of }TiCl_4\times \text{Molar mass of }TiCl_4$

$\text{Mass of }TiCl_4=(0.455mole)\times (190g/mole)=86.45g$

Therefore, the theoretical yield will be 86.45 grams.

4 0

3 years ago