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vova2212 [387]
3 years ago
9

Calculate the speed of a wave with a wavelength of 6 meters and a frequency of 3 hertz.

Chemistry
2 answers:
kupik [55]3 years ago
4 0
Painted 18 because the wave length is 6 m and the frequency is 3.So 6×3 = 18
Kruka [31]3 years ago
3 0

The answer is 18 you multiply wavelength (6) times frequency (3)
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One of the intermediates in the synthesis of glycine from ammonia, carbon dioxide, and methane is aminoacetonitrile, C2H4N2.
mart [117]

Answer:

  • <em>You could expect 3.48 grams of C₂H₄N₂</em>

Explanation:

You must start by stating the chemical equation for the reaction of ammonia, carbon dioxide, and methane to produce aminoaceto nitrile.

1. Word equation:

Ammonia + Carbon dioxide + Methane → Aminoacetonitrile + Water

2. Balanced chemical equation:

       8NH_3+5CO_2+3CH_4\rightarrow 4C_2H_4N_2 +10H_2O

3. Convert the mass of each reactant into number of moles:

<u>Formula:</u>

  • Number of moles = mass in grams/molar mass

<u>2.11g NH₃</u>

  • Number of moles = 2.11g / 17.03g/mol = 0.124 mol NH₃

<u>14.9g CO₂</u>

  • Number of moles = 14.9g/44.01g/mol = 0.339 mol CO₂

<u>1.75g CH₄</u>

  • Number of moles = 1.75g/16.04g/mol = 0.109 mol CH₄

4. Theoretical mol ratio

From the balanced chemical equation, using the coefficientes:

         8molNH_3:5molCO_2:3molCH_4:4molC_2H_4N_2:10molH_2O

5. Limiting reagent

The available amounts of the reactants are:

  • 0.124 mol NH₃
  • 0.339 mol CO₂
  • 0.109 mol CH₄

Fom the theoretical mole ration, to react with 0.124 mol of NH₃ you would need:

  • 0.124molNH₃ × (5molCO₂/8molNH₃) = 0.0775 mol CO₂

Since there are 0.339 moles available, this is in excess.

  • 0.124molNH₃ × (3molCH₄/8molNH₃) =  0.0465mol CO₂

Since there are 0.109 moles available, this is in excess too.

Hence, the limiting reagent is NH₃.

6. Yield

Use the theoretical ratio:

  • 0.124molNH₃ × (4molC₂H₄N₂ / 8molNH₃) = 0.0620 mol C₂H₄N₂

Convert to grams:

  • Mass = number of moles × molar mass
  • 0..0620 mol × 56.068g/mol = 3.48 g of C₂H₄N₂ ← answer

4 0
3 years ago
BALANCE THIS EQUATION:<br> C4H10 + O2 = C02 + H20
Lostsunrise [7]

Answer:

{ \rm{C _{4} H_{10}+  \frac{13}{2} O _{2} = 4C0 _{2} + 5H _{2}0}} \\

5 0
3 years ago
4Fe+3O2<br><br> I really have no idea how to do this.. HELP
Jlenok [28]
Reorder 4Fe and 3O2.
3O2 + 4Fe
3 0
3 years ago
The radioisotope radon-222 has a half-life of 3.8 days. How much of a 198.6 g sample of radon-222 would be left after approximat
bagirrra123 [75]
The radon-222 sample has a half-life of 3.8 days, and we are asked how many times would the mass divide in half after 23 days. First we calculate the amount of times division occurs by taking the number of days and dividing that by the number of days for one half-life to occur: 23/3.8 = 6.05.

We have 198.6 grams of sample, and we are going to divide it in half 6 times to determine how much of it remains after 23 days:
198.6/2 = 99.3 grams
99.3/2 = 49.65 grams
49.65/2 = 24.83 grams
24.83/2 = 12.41 grams
12.41/2 = 6.21 grams
6.21/2 = 3.1 grams

Therefore, we are left with 3.1 grams of radon-222 after 23 days if one half-life equals to 3.8 days.
7 0
3 years ago
In Thomson’s model of the atom , what parts of the atom were in motion
trasher [3.6K]

Answer:

The electrons where in motion

4 0
3 years ago
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