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almond37 [142]
2 years ago
14

A type of friction that opposes the motion of an object traveling either through liquid or gas

Chemistry
1 answer:
Lunna [17]2 years ago
3 0

type of friction that opposes the motion of an object traveling either through liquid or gas is known as <u>drag</u><u>.</u>

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Whoever awser correct I will give you Brainly
vivado [14]

Answer:

Option A.

2Na + 2H2O —> 2NaOH + H2

Explanation:

To know which option is correct, we shall do a head count of the number of atoms present on both side to see which of them is balanced. This is illustrated below below:

For Option A:

2Na + 2H2O —> 2NaOH + H2

Reactant >>>>>>> Product

2 Na >>>>>>>>>>> 2 Na

4 H >>>>>>>>>>>> 4 H

2 O >>>>>>>>>>>> 2 O

Thus, the above equation is balanced.

For Option B:

2Na + 2H2O —> NaOH + H2

Reactant >>>>>>> Product

2 Na >>>>>>>>>>> 1 Na

4 H >>>>>>>>>>>> 3 H

2 O >>>>>>>>>>>> 1 O

Thus, the above equation is not balanced.

For Option C:

2Na + H2O —> 2NaOH + H2

Reactant >>>>>>> Product

2 Na >>>>>>>>>>> 2 Na

2 H >>>>>>>>>>>> 4 H

1 O >>>>>>>>>>>> 2 O

Thus, the above equation is not balanced.

For Option D:

Na + 2H2O —> NaOH + 2H2

Reactant >>>>>>> Product

1 Na >>>>>>>>>>> 1 Na

4 H >>>>>>>>>>>> 5 H

2 O >>>>>>>>>>>> 1 O

Thus, the above equation is not balanced.

From the illustrations made above, only option A is balanced.

7 0
2 years ago
How much heat is needed to condense 22.25 grams of nitrogen gas at â€""195.8°c? the latent heat of vaporization of nitrogen is
Margaret [11]

As per the question, the mass of the nitrogen gas m = 22.25 gram.

The latent heat of vaporization of nitrogen = 199.0 j/g

As per the question, the nitrogen gas will condense. During condensation, the nitrogen gas will lose or release heat equal to its latent heat.

Hence, the heat released by nitrogen gas Q = ml = 22.25 × 199.0 J                                                                           = 4427.75 J.

Hence, the amount of heat released will be 4427.75 J.

<h3>How can you figure out how much heat is in each gram?</h3>

The formula: can be utilized to determine energy. Q = mc ∆T. In the equation, Q stands for energy expressed in joules or calories, m for mass expressed in grams, c for specific heat, and T for temperature change, which is the difference between the final temperature and the initial temperature. Water has a specific heat of 1 calorie/gram °C.

Learn more about energy here:

brainly.com/question/1932868

#SPJ4

8 0
1 year ago
An artificial reef is intended to affect the ocean ecosystem by<br>​
Ber [7]

Answer:

By strengthening the weak coral that is on the reef.

5 0
2 years ago
Read 2 more answers
When light rays appear to be coming from behind a mirror, what type of image has been formed
rusak2 [61]
The image<span> formed by a plane </span>mirror<span> is always virtual (meaning that the light rays </span>do<span> not actually come from the </span>image<span>), upright, and of the same shape and size as the object it is reflecting. A virtual </span>image<span> is a copy of an object formed at the location from which the light rays </span>appear<span> to come.</span>
8 0
2 years ago
Read 2 more answers
Jodi reacts 6.087 grams of cobalt (mw=58.933) with a solution containing excess gold (iii) chloride and recovers 13.572 g of sol
Makovka662 [10]

The correct answer is reaction 2 most likely occurred in their experiment.

So the given two reactions are as follows:

1) Au³⁺(aq) + Co(s) --> Au(s) + Co³⁺(aq)

2) 2Au³⁺(aq) + 3Co(s) --> 2Au(s) + 3Co³⁺(aq)

Mass of Co = 6.087 g

Molar mass of Co = 58.933 g/mol

Moles of Co =\frac{6.087 g}{58.933 g/mol} = 0.1032

Mass of Au = 13.572 g

Molar mass of Au = 196.967 g/mol

Moles of Au = \frac{13.572 g}{196.967 g/mol} = 0.069

Now based on reaction 1) the molar ratio between Co and Au is 1:1

So as per this reaction 0.1032 moles of Co would produce 0.1032 mole of Au

Again based on reaction 2) the molar ratio between Co and Au is 3:2

So as per this reaction 0.1032 moles of Co would produce \frac{2 x 0.1032}{3} mole of Au

or, As per the second reaction 0.1032 moles of Co would produce 0.0688 moles of Au

8 0
3 years ago
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