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sergejj [24]
3 years ago
5

How do the interactions that are broken in water when it is boiled compare with those broken when water is electrolyzed? Boiling

water breaks intermolecular attractions and electrolysis breaks covalent bonds. Boiling water breaks covalent bonds and electrolysis breaks intermolecular attractions. Boiling water and electrolysis of water break covalent bonds. Boiling water and electrolysis of water break intermolecular forces.
Chemistry
1 answer:
nasty-shy [4]3 years ago
8 0

Answer:

Boiling water breaks intermolecular attractions and electrolysis breaks covalent bonds.

Explanation:

When water boils, hydrogen bonds are broken between adjacent water molecules. The hydrogen bond is an intermolecular bond between adjacent oxygen and hydrogen atoms of water molecules.  

During electrolysis, water dissociates in the presence of electric current. Here, ions are formed in the process. Therefore, covalent bonds are broken here.

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sergeinik [125]

Answer : The molarity of KF in the solution is 1.5 M.

Explanation : Given,

Moles of KF = 3.0 mol

Volume of solution = 2.00 L

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Formula used :

\text{Molarity}=\frac{\text{Moles of }KF}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{3.0mol}{2.00L}=1.5mole/L=1.5M

Therefore, the molarity of KF in the solution is 1.5 M.

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3 years ago
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3 years ago
The gas phase decomposition of sulfuryl chloride at 600 K SO2Cl2(g)SO2(g) + Cl2(g) is first order in SO2Cl2. During one experime
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Answer: The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

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a - x = amount left after decay process  = 3.06\times 10^{-4}

559min=\frac{2.303}{k}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=\frac{2.303}{559}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

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The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

6 0
3 years ago
Calculating molarity using solute moles A chemist prepares a solution of sodium chloride (NaCl) by measuring out 6.89 mol of sod
hram777 [196]

Answer: Concentration of the chemist's sodium chloride solution is 34.4 mol/L.

Explanation:

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n= moles of solute

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7 0
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