Answer:
the Answer is B
Explanation:
If resources are being used faster than they are being replenished, then the species has exceeded its carrying capacity. If this occurs, the population will then decrease in size. Every stable population has one or more factors that limit its growth. A limiting factor determines the carrying capacity for a species.
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Answer:
Partial pressure of
in the gas was 733 torr and mass of
in the sample was 2.12 g.
Explanation:
a) Total pressure of gas = (partial pressure of water vapour)+(partial pressure of
)
Here partial pressure of water vapour is 21 torr and total pressure of gas is 754 torr.
So, partial pressure of
= (total pressure of gas)-(partial pressure of water vapour) = (754 torr) - (21 torr) = 733 torr
b) Lets assume that
behaves ideally. Hence-
PV=nRT
where P is pressure of
, V is volume of
, n is number of moles of
, R is gas constant and T is temperature in kelvin
here P = 733 torr =
= 0.9646 atm
V = 0.65 L, R = 0.082 L.atm/(mol.K), T=(273+22)K = 295 K
So, 
= 
= 0.0259 moles
As 3 moles of
are produced from 2 moles of
therefore 0.0259 moles of
are produced from
moles or 0.0173 moles of
.
Molar mass of
= 122.55 g
So mass of
in sample = 
= 2.12 g
Answer:
.224 M
Explanation:
To begin, we need to find the molar mass of Na2S
To find Molarity, we use the equation M=moles/Liters of solution
We are given grams, so we must divide by the molar mass of Na2S to find moles.
- 8.76g Na2S / 78.05g/mol Na2S= .112 moles
Now we use our Molarity equation:
- .112 moles Na2S / .500L of solution = .224 M