Answer:
b. 0.22 L
Explanation:
Step 1: Write the balanced equation
4 HNO₃(l) ⇒ 4 NO₂(g) + 2 H₂O(l) + O₂(g)
Step 2: Calculate the moles corresponding to 2.5 g of HNO₃
The molar mass of HNO₃ is 63.01 g/mol.
2.5 g × 1 mol/63.01 g = 0.040 mol
Step 3: Calculate the moles of O₂ produced from 0.040 moles of HNO₃
The molar ratio of HNO₃ to O₂ is 4:1. The moles of O₂ produced are 1/4 × 0.040 mol = 0.010 mol.
Step 4: Calculate the volume corresponding to 0.010 moles of O₂
Assuming the reaction takes place at standard temperature and pressure, the volume of 1 mole of O₂ is 22.4 L.
0.010 mol × 22.4L/1 mol = 0.22 L
