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lora16 [44]
3 years ago
15

Nitric acid decomposes in light to form nitrogen dioxide, water, and oxygen, according to the following chemical equation.

Chemistry
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

b. 0.22 L

Explanation:

Step 1: Write the balanced equation

4 HNO₃(l) ⇒ 4 NO₂(g) + 2 H₂O(l) + O₂(g)

Step 2: Calculate the moles corresponding to 2.5 g of HNO₃

The molar mass of HNO₃ is 63.01 g/mol.

2.5 g × 1 mol/63.01 g = 0.040 mol

Step 3: Calculate the moles of O₂ produced from 0.040 moles of HNO₃

The molar ratio of HNO₃ to O₂ is 4:1. The moles of O₂ produced are 1/4 × 0.040 mol = 0.010 mol.

Step 4: Calculate the volume corresponding to 0.010 moles of O₂

Assuming the reaction takes place at standard temperature and pressure, the volume of 1 mole of O₂ is 22.4 L.

0.010 mol × 22.4L/1 mol = 0.22 L

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Masja [62]

Answer:

True

Explanation:

hope it'll help!!

4 0
3 years ago
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Which type of orbital will be occupied by the electrons of highest energy for the Si^4+ ground-state ion? 1. 2s 2. 3p 3. 4s 4. 4
Shtirlitz [24]

Answer: Option (5) is the correct answer.

Explanation:

It is known that the ground state electronic configuration of silicon is [Ne]3s^{2}3p^{2}.

And, we know that when an atom tends to gain an electron then it acquires a negative charge and when an atom tends to lose an electron then it acquires a positive charge.

As Si^{4+} has a +4 charge which means that it has lost 4 electrons. Hence, the electronic configuration of Si^{4+} is 1s^{2}2s^{2}2p^{6}.

According to the Aufbau principle, in the ground state of an atom or ion the electrons fill atomic orbitals of the lowest energy levels first, before filling the higher energy levels.

As 2p orbital is filled after the filling of 2s orbital.

Therefore, we can conclude that 2p orbital will be occupied by the electrons of highest energy for the Si^{4+} ground-state ion.

4 0
3 years ago
2. HOW MUCH HEAT IS REQUIRED TO BE RELEASED WHEN
jarptica [38.1K]

Answer: -112200J

Explanation:

The amount of heat (Q) released from an heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = ?

Mass of water vapour = 30.0g

C = 187 J/ G°C

Φ = (Final temperature - Initial temperature)

= 100°C - 120°C = -20°C

Then apply the formula, Q = MCΦ

Q = 30.0g x 187 J/ G°C x -20°C

Q = -112200J (The negative sign does indicates that heat was released to the surroundings)

Thus, -112200 joules of heat is released when cooling the superheated vapour.

5 0
4 years ago
A 8L sample of gas at 250 K is cooled to 75 K. What is the volume of the gas after it is cooled?
Stells [14]

by \: Charles'\: law: \:  \\  \frac{v_{1}}{t_{1}}  =  \frac{v_{2}}{t_{2}}  \\

Where v is the volume(in L) and t is the temperature(in °K)

\frac{8}{250}  =  \frac{v_{2}}{75} \\\\4/5 =v_2/3 \\\\\boxed{v_{2} = \frac{12}{5}}\\\\\\\huge{=2.5 l}

7 0
2 years ago
Hydrazine, N2H4, may react with oxygen to form nitrogen gas and water.
Sindrei [870]

Answer:

The percent yield of the reaction is 35 %

Explanation:

In the reaction, 1 mol of hydrazine reacts with 1 mol O₂ to produce 1 mol of nitrogen and 2 moles of water.

Let's verify the moles that were used in the reaction.

2.05 g . 1mol/ 32 g = 0.0640 mol

In the 100% yield, 1 mol of hydrazine produce 1 mol of N₂ so If I used 0.0640 moles of reactant, I made 0.0640 moles of products.

Let's use the Ideal Gases Law equation to find out the real moles of nitrogen, I made (real yield).

1atm . 0.550L = n . 0.082 . 295K

(1atm . 0.550L) / 0.082 . 295K = n → 0.0225 moles

Percent yield of reaction = (Real yield / Theoretical yield) . 100

(0.0225 / 0.0640) . 100 = 35%

3 0
3 years ago
Read 2 more answers
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