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Nesterboy [21]
4 years ago
6

What is included in a compaarative investigation

Chemistry
1 answer:
Minchanka [31]4 years ago
6 0

a scientific question

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Why are cars manufactures exploring hydrogen fuel cell technology as a possiable replacement for gasoline burning engines
horsena [70]
To possibly take down on the pollution we produce in the world
4 0
3 years ago
An electric current transports 93.0 C of charge in 601 milliseconds. Calculate the size of the electric current. Be sure your an
Elina [12.6K]

Answer:

155 A

Explanation:

Given data

  • Transported charge (Q): 93.0 Coulomb
  • Elapsed time (t): 601 ms = 0.601 seconds

We can determine the magnitude of the electric current (I) using the following expression.

I = Q / t

I = 93.0 C / 0.601 s

I = 155 C/s

I = 155 A

The magnitude of the electric current is 155 Ampere.

6 0
4 years ago
What element is undergoing oxidation in the following reaction?. . CH4(g) +2O2 (g) -> CO2(g) +2H2O(g). . . option . a) C. b)
SVETLANKA909090 [29]
The correct answer is a.) C. Oxidation occurs when an element loses electrons and increases its oxidation state. In the chemical equation, Carbon in CH4 has an oxidation state of 4- while Carbon in CO2 has an oxidation of 4+.
4 0
3 years ago
Read 2 more answers
A reaction vessel contains 10.0 g of CO and 10.0 g of O2. How many grams of CO2 could be produced according to the following rea
iren2701 [21]

Answer:

1. 15.71 g CO2

2. 38.19 % of efficiency

Explanation:

According to the balanced reaction (2 CO(g) + O2(g) → 2 CO2(g)), it is clear that the CO is the limitant reagent, because for every 2 moles of CO we are using only 1 mole of O2, so even if we have the same quantity for both reagents, not all of the O2 will be consumed. This means that we can just use the stoichiometric ratios of the CO and the CO2 to solve this question, and for that we need to convert the gram units into moles:

For CO:

C = 12.01 g/mol

O = 16 g/mol

CO = 28.01 g/mol

(10.0g CO) x (1 mol CO/28.01 g) = 0.3570 mol CO

For CO2:

C = 12.01 g/mol

O = 16 x 2 = 32 g/mol

CO2 = 44.01 g/mol

We now that for every 2 moles of CO we are going to get 2 moles of CO2, so we resolve as follows:

(0.3570 mol CO) x (2 mol CO2/2 mol CO) = 0.3570 moles CO2

We are obtaining 0.3570 moles of CO2 with the 10g of CO, now lets convert the CO2 moles into grams:

(0.3570 moles CO2) x (44.01 g/1 mol CO2) = 15.71 g CO2

Now for the efficiency question:

From the previous result, we know that if we produce 15.71 CO2 with all the 10g of CO used, we would have an efficiency of 100%. So to know what would that efficiency be if we would only produce 6g of CO2, we resolve as follows,

(6g / 15.71g) x 100 = 38.19 % of efficiency

6 0
3 years ago
What happens when a covalent bond vs. an ionic bond is formed?
Bas_tet [7]

Explanation:

Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals. ... A covalent bond involves a pair of electrons being shared between atoms. Atoms form covalent bonds in order to reach a more stable state.

4 0
3 years ago
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