Answer:
-36x z^2 ( 10 y^2 z^2) ^ 1/3
Step-by-step explanation:
16. -9 ( 640 x^3 y^2 z^8) ^ 1/3
^1/3 is the cubed root
First I will separate
(ab)^y = a^y * b^y
-9 ( 640 ) ^ 1/3 x^3 ^ 1/3 y^2 ^ 1/3 z^8 ^ 1/3
Then we know a^b^c = a^(b*c)
-9 (64) ^ 1/3 (10)^ 1/3 x^(3 * 1/3) y^(2 *1/3) z^(8* 1/3)
Simplify
-9 (64) ^ 1/3 (10)^ 1/3 x^(1) y^(2 /3) z^(8/3)
-9* 4 (10)^ 1/3 x y^(2 /3) z^(8/3)
When the exponent is greater than 1, we can take out the whole number
z^ 8/3 = x^2 * x^2/3 for example
-9 *4 (10)^ 1/3 x y^(2 /3) z^2 z^(2/3)
Move everything to the left without fractional exponents
-36x z^2 ( 10 y^2 z^2) ^ 1/3
Answer:
27
Step-by-step explanation:
Alternatively, the lcm of 9 and 27 can be found using the prime factorization of 9 and 27: The prime factorization of 9 is: 3 x 3. The prime factorization of 27 is: 3 x 3 x 3. Eliminate the duplicate factors of the two lists, then multiply them once with the remaining factors of the lists to get lcm(9,9) = 27.
Answer:
The P-value is less than 0.005
Step-by-step explanation:
took the test good luck!
Answer:
YES
Step-by-step explanation:
The blanks would be (5 x 6) - (5 x 3) hope this helps :)
You times it by one and then add the two zeros so your answer is 3,500